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Minchanka [31]
4 years ago
9

Which statements about Earth’s atmosphere are correct

Physics
1 answer:
kirill [66]4 years ago
4 0
All of them are correct
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A 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s what is the net force on the car
Ksenya-84 [330]

Answer: 20496N

Explanation:

The formula to calculate the net force will be given as:

Net force = Acceleration × Mass

Since 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s, the net force would be:

= 10248 × 2

= 20496N

8 0
3 years ago
Sometimes my music is played value can feel your body shaking explain what is happening in terms of resonance?
Jet001 [13]

Answer:

If you are standing next to loud music you will feel yourself vibrating because resonance happens. When an object vibrating at or near the resonant frequency of a second object then it causes the second object to vibrate. This phenomenon is called resonance.

Explanation:

Hope this helped! :))

8 0
3 years ago
Two football players run towards each other along a straight path in Penrith Park in the clash between the Melbourne storms and
Agata [3.3K]

Answer:

a) v = 0.4799 m / s,  b)  K₀ = 1600.92 J,    K_f = 5.46 J

Explanation:

a) How the two players collide this is a momentum conservation exercise. Let's define a system formed by the two players, so that the forces during the collision are internal and also the system is isolated, so the moment is conserved.

Initial instant. Before the crash

        p₀ = m v₁ + M v₂

where m = 95 kg and his velocity is v₁ = -3.75 m / s, the other player's data is M = 111 kg with velocity v₂ = 4.10 m / s, we have selected the direction of this player as positive

Final moment. After the crash

       p_f = (m + M) v

as the system is isolated, the moment is preserved

       p₀ = p_f

       m v₁ + M v₂ = (m + M) v

       v =\frac{m v_1 + M v_2}{m+M}

let's calculate

        v = \frac{ -95 \ 3.75 \ + 111 \ 4.10}{95+111}

        v = 0.4799 m / s

b) let's find the initial kinetic energy of the system

         K₀ = ½ m v1 ^ 2 + ½ M v2 ^ 2

         K₀ = ½ 95 3.75 ^ 2 + ½ 111 4.10 ^ 2

         K₀ = 1600.92 J

the final kinetic energy

         K_f = ½ (m + M) v ^ 2

         k_f = ½ (95 + 111) 0.4799 ^ 2

         K_f = 5.46 J

3 0
3 years ago
Figure 23.9 shows a sliding mass on a spring. Assume there is no friction.
Tom [10]
<span>Without friction, there will be undamped simple harmonic motion. The force of the spring is proportional to the distance from the equilibrium point. The period of oscillation will be independent of the amplitude.

I hope my answer has come to your help. God bless and have a nice day ahead!</span>
4 0
3 years ago
What would happen if a group of force of 45 N compete against a group of 50 N
larisa [96]
The 50N group of force would be greater
So whichever object is being pulled will be pulled towards the 50N force
7 0
3 years ago
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