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drek231 [11]
3 years ago
9

A hit-and-run incident is one of the more common cases for paint evidence. true or false

Physics
1 answer:
AleksandrR [38]3 years ago
4 0
The statement "<span>A hit-and-run incident is one of the more common cases for paint evidence." is true.  This is shown by a</span><span> spot close to the point of impact, but in a place that has not been damaged.</span>
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Rebecca jogs in place for two minutes before her track meet. Rebecca weighs 100 pounds. Which of the following statements is tru
MrRissso [65]
The answer is A because it was 2 minutes and she weighs 100 lbs.... so 2(100)=200.... 200 lbs of work
7 0
3 years ago
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A professor sits at rest on a stool that can rotate without friction. The rotational inertia of the professor-stool system is 4.
Anestetic [448]

Answer:

\omega=0.37 [rad/s]  

Explanation:

We can use the conservation of the angular momentum.

L=mvR

I\omega=mvR

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

(I_{proffesor - stool}+mR^{2})\omega=mvR

Now, we just need to solve it for ω.

\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}

\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}      

\omega=0.37 [rad/s]  

I hope it helps you!

5 0
4 years ago
On a smooth horizontal floor an object
lukranit [14]

Answer:

what do you mean by this?

Explanation:

7 0
3 years ago
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A spherical shell has inner radius 1.5 m, outer radius 2.5 m, and mass 850 kg, distributed uniformly throughout the shell. What
Nimfa-mama [501]

Answer:

The magnitude of the gravitational force is 4.53 * 10 ^-7 N

Explanation:

Given that the magnitude of the gravitational force is F = GMm/r²

mass M = 850 kg

mass m = 2.0 kg

distance d = 1.0 m , r = 0.5 m

F = GMm/r²

Gravitational Constant G = 6.67 × 10^-11 Newtons kg-2 m2.

F = (6.67 × 10^-11 * 850 * 2)/0.5²

F = 0.00000045356 N

F = 4.53 * 10 ^-7 N

3 0
3 years ago
Iron + Hydrochloric acid --&gt; ?
marusya05 [52]
<h3>Iron - Fe</h3>

<h3>Hydrochloric Acid- HCl</h3>

<h2><u>Solution</u></h2>

\bold{Fe  +2HCl \rightarrow FeCl _{}{ \tiny2}  + H{ \tiny{2}}}

\therefore \bold{\fbox{{Balanced}}}

Iron + Hydrochloric Acid \rightarrow Ferrous Chloride + Hydrogen

<h2>Hope This Helps You ❤️</h2>
8 0
3 years ago
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