All categories

2 years ago

Why does the North star not move but the other stars move

Physics

1 answer:

blsea [12.9K]2 years ago

3 0

Answer:

it's the star in the center of the star field

Explanation:

Why Doesn't Polaris Move? Polaris is very distant from Earth, and located in a position very near Earth's north celestial pole. ... Polaris is the star in the center of the star field; it shows essentially no movement. Earth's axis points almost directly to Polaris, so this star is observed to show the least movement

You might be interested in

A pendulum clock is taken to the moon (g = 1.6 N/kg). How long must the pendulum be in order for the clock to

mamaluj [8]

Answer:

0.041 m

Explanation:

T = 2π√(L/g)

1 s = 2π√(L / (1.6 N/kg))

L = 0.041 m

4 0

3 years ago

A boat was traveling at 15 mph when a passenger threw an object at 10 mph in the same direction the boat was moving. A friend,

Slav-nsk [51]

Answer:

the person on the boat is moving 15mph on the boat and throws the ball 10mph. you add that together its 25mph. the other person is standing on land so their is no extra speed.

Explanation:

its common

3 0

2 years ago

What upward gravitational force does a 5600kg elephant exert on the earth?

Anastaziya [24]

Force is determined by multiplying mass and gravity (F= mg). To determine the answer, the mass of the elephant (5600 kg) is multiplied with the gravity (9.8 m/s²). The answer is 5800 N. This is the upward gravitational force that the elephant exerts on the earth.

8 0

3 years ago

Read 2 more answers

Calculate the energy needed to heat 4 kg of water from 25°C to 45°C.

inna [77]

(1 cal/g °C) x (4000 g) x (45 - 25)°C = 80000 cal = 80 kcal. So the answer is 80 kcal .

8 0

3 years ago

Read 2 more answers

Help meh in this question plzzz <br>

iragen [17]

The Moment of Inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

Where:

$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):