Help please, this is unit about work, power, force in physics.
1 answer:
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Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;
(a) the force constant of the spring
(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k
Answer:
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Explanation:
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Answer:
Explanation:
From the question we are told that:
Frequency of 3rd harmonics
Frequency of 5th harmonics
Generally the equation for Wavelength at 3rd Harmonics is mathematically given by
Therefore
Generally the equation for Wavelength at 1st Harmonics is mathematically given by
Therefore
Generally the equation for the frequency of the first harmonic is mathematically given by