To solve this problem we will apply the energy conservation theorem for which the work applied on a body must be equivalent to the kinetic energy of this (or vice versa) therefore
Here,
m = mass
= Velocity (Final and initial)
First case) When the particle goes from 10m/s to 20m/s
Second case) When the particle goes from 20m/s to 30m/s
As the mass of the particle is the same, we conclude that more energy is required in the second case than in the first, therefore the correct answer is A.
Answer:
A) Spherically symmetric about a point in the constellation Sagittarius and concentrated in that direction
Explanation:
The globular clusters are present mainly in the direction of Sagittarius with the center of the system of globular cluster being measured as a spherical cluster cloud such that the center of the Milky Way can be taken as being in the Sagittarius constellation
Answer:
-27.3 m/s
Explanation:
Given:
y₀ = 38 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2 (-9.8 m/s²) (0 m − 38 m)
v = -27.3 m/s
Or, you can solve with energy.
PE = KE
mgh = ½ mv²
v² = 2gh
v = -27.3 m/s
Answer:
The average velocity is 8 unit per sec
Explanation:
Given as :
The Distance x = 20 - 4t² unit
Change in time Δt = ( 2 - 0 ) s = 2 s
Let the velocity = V unit/s
∴ V = 
Or, V = - 8t unit/s
Now velocity at t = 0
V1 = - 8 × 0 = 0 unit/s
And velocity at t = 2 sec
V2 = - 8 × 2 = - 16
So, Average velocity = 
= 
= -8
Or, 
= 8 unit/sec
Hence The average velocity is 8 unit per sec Answer
