All categories

3 years ago

Newtons first law of motion states that the velocity of an object doesn’t change if the forces acting on the object are

1 answer:

4 0

Balenced

Think of it this way if 2 same weight and same speed objects were racing toward each other perfectly straight then their forces will cancel out and the movement afterwords will be 0

You might be interested in

angela uses a force of 25 newtons to lift her grocery bag while doing 50 joules of work. how far did she lift the grocery bags

Evgen [1.6K]

We know that:
W=Fs
50J=25N*s
s=50J/25N
s=2m

5 0

3 years ago

A meteor is falling towards the earth. If the mass and the radius of the earth are 6×10^24kg and 6.4×10^3km respectively,find th

Klio2033 [76]

Answer:

h = 3600 km

Explanation:

Given,

The mass of the Earth, M = 6 x 10²⁴ km

The radius of the Earth, R = 6.4 x 10³ km

The acceleration of the meteor at height, x = 4 m/s²

The acceleration due to gravity at the surface of the Earth is given by the formula,

g = GM/R²

At height 'h' acceleration is given by the formula,

gₓ = GM/Rₓ²

Rₓ² = GM/gₓ

= 6.673 x 10⁻¹¹ X 6 x 10²⁴ / 4

= 1 x 10¹⁴

Rₓ = 1 x 10⁷ m

Where,

Rₓ = R + x

x = Rₓ - R

= 10000 km - 6400 km

= 3600 km

Hence, the height of the meteor where its acceleration due to gravity is 4 m/s² is, h = 3600 km

4 0

4 years ago

two ice skaters push each other, and move in opposite directions. the mass of one is 75 kg, and his speed is 2 m/s. if the mass

sattari [20]

momentum conservation

75x2 = 30 x her speed

75x2/30=150/30=5m/s

7 0

4 years ago

People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

NISA [10]

Answer:

Explanation:

Torque on a loop in a magnetic field

Maximum torque = M B

M is magnetic moment of loop and B is magnetic field

M = area x current

= 3.14 x .10² x i

Maximum torque = M B

1 x 10⁻³ = 3.14 x .10² x i x .65 x 10⁻⁴

i = 490 A

Current = 490 A.

3 0

3 years ago

A wire loop is suspended from a string that is attached to point P in the drawing. When released, the loop swings downward, from

Naddik [55]

Complete Question

The complete question iws shown on the first uploaded image

Answer:

$y \to z \to x$

$x \to z \to y$

Explanation:

Now looking at the diagram let take that the magnetic field is moving in the x-axis

Now the magnetic force is mathematically represented as

$F = I L$ x B

Note (The x is showing cross product )

Note the force(y-axis) is perpendicular to the field direction (x-axis)

Now when the loop is swinging forward

The motion of the loop is from y to z to to x to y

Now since the force is perpendicular to the motion(velocity) of the loop

Hence the force would be from z to y and back to z

and from lenze law the induce current opposes the force so the direction will be from y to z to x

Now when the loop is swinging backward

The motion of the induced current will now be x to z to y

5 0

3 years ago