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3 years ago

6

A person sitting in a chair with wheels stands up, causing the chair to roll backward across the floor. How would you describe t

he momentum of the chair?

1 answer:

OleMash [197]3 years ago

3 0

Scenes the chair wheels are up the person is rolling backwards and if the wheels were down then the person would go forwards
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Where does matter come from?

Pie

The Big Bang theory is matter and energy in the universe exploded out from one point. As the explosion occurred, energy and matter spread outward and formed the universe. The matter from the Big Bang formed clouds of gas.

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3 years ago

How did the magnet’s density measurement using the Archimedes’ Principle compare to the density measurement using the calculated

guapka [62]

Answer:

The two methods will yield different results as one is subject to experimental errors that us the Archimedes method of measurement, the the density measurement method will be more accurate

Explanation:

This is because the density method using the calculated volume will huve room for less errors that's occur in practical method i.e Archimedes method due to human error

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3 years ago

Choose the correct words from the box to complete the definition of resistance.

zzz [600]

Answer:

Opposition of passing a electric circuit

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3 years ago

A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal

Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

$a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2$

Let d be the breaking distance. It can be calculated using third equation of motion as :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m$

So, the required distance covered by the car is 44.64 m.

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3 years ago

Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni

joja [24]

Answer:

Explanation:

Use the following equation:

$E=\frac{q}{F}$ and solve for F:

$F=\frac{q}{E}$ and filling in:

$F=\frac{.0600}{1500}$

F = 4.0 × $10^{-4$ N

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3 years ago