The speed of a proton after it accelerates from rest through a potential difference of 350 V is .
Initial velocity of the proton
Given potential difference
let's assume that the speed of the proton is ,
Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge when accelerated with a potential difference is,
Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy P.E must be equal to gain in Kinetic Energy K.E</em> i.e
If the initial and final velocity of the proton is and respectively then,
change in Kinetic Energy
change in Potential Energy
from conservation of energy,
so,
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Answer:
Distance of the point where electric filed is 2.45 N/C is 1.06 m
Explanation:
We have given charge per unit length, that is liner charge density
Electric field E = 2.45 N/C
We have to find the distance at which electric field is 2.45 N/C
We know that electric field due to linear charge is equal to
, here is linear charge density and r is distance of the point where we have to find the electric field
So
r = 1.06 m
So distance of the point where electric filed is 2.45 N/C is 1.06 m
Answer:
150 steps south
Explanation:
250 north 250 back to start then continue south for remainder of 400 steps. 150 south
Answer:
The second one a part of it heats up Earth's land and water equally.
Explanation:
Hope this help!!!
Alike because they both act on the quarks making up the nucleons and they have very short ranges. The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei. Which also makes them very different