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ella [17]
3 years ago
5

How does reflection differ from refraction and diffraction?

Physics
1 answer:
Otrada [13]3 years ago
5 0
Reflection, i<span>t is the phenomena of getting back the light you've shown from a light source with the same angle. r</span>efraction, <span>It is the phenomena of bending of light when it changes it medium. This </span>can<span> rarer to denser or denser to rarer. d</span>iffraction,<span> It is the phenomena of bending of light near the edges of the object. hope this helps

</span>
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What is the difference between elastic force and gravitational force?
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There are four fundamental forces. Gravitational is one. Elastic is produced by Electrostatic Force( a different fundamental force!)
Gravity has an infinite range. Elecrotrostatic forces reduce significantly as charges move away small distances but are relatively strongly felt. We feel the forces pulling on us when we stretch rubber. But two large balls side by side will not be significantly attracted by their tiny gravitational forces!
4 0
3 years ago
Explain retrograde motion and why it confused early astronomers as they viewed the motion of objects in the sky.
Masteriza [31]

Answer:

Explanation:

Retrograde motion in astronomy is, in general, orbital or rotational motion of an object in the direction opposite the rotation of its primary, that is, the central object (right figure). It may also describe other motions such as precession or nutation of an object's rotational axis. Prograde or direct motion is more normal motion in the same direction as the primary rotates. However, "retrograde" and "prograde" can also refer to an object other than the primary if so described. The direction of rotation is determined by an inertial frame of reference, such as distant fixed stars.

3 0
3 years ago
Read 2 more answers
Calculate the equivalent resistance of the circuit below.
expeople1 [14]

Answer:

30Ω

Explanation:

To calculate the equivalent resistance in the circuit, do the following:

Step 1:

10Ω and 20Ω are in series connection. Therefore their equivalent is: 10 + 20 = 30Ω

Step 2:

The equivalent resistance (30Ω) obtained from the above is in parallel connection with 30Ω resistance shown in the diagram above.

Therefore their equivalent is given by:

1/30 + 1/30 = 2/30 = 1/15.

Now invert to obtain the equivalent

Therefore, the equivalent is 15Ω

Step 3:

Determination of the overall equivalent of the resistance of the circuit.

The new equivalent resistance 15Ω obtained above is in series connection with 15Ω resistance in the diagram above.

Therefore their equivalent is given by:

15Ω + 15Ω = 30Ω

Therefore, the equivalent resistance in the circuit is 30Ω

7 0
3 years ago
Two blocks of masses M and 2M are initially traveling at the same speed v but in the opposite directions. They collide and stick
Hatshy [7]

Answer:

Explanation:

Given

Two masses M and 2 M with velocity v in opposite direction

After collision they stick together

Initial momentum

P_i=Mv-2Mv

final momentum

P_f=3Mv'

Conserving momentum

P_i=P_f

-Mv=3Mv'

v'=\frac{v}{3}

i.e. system moves towards the direction of 2M mass

Initial kinetic Energy K_1=\frac{1}{2}Mv^2+\frac{1}{2}2Mv^2

K_1=\frac{3}{2}Mv^2

Final Kinetic Energy K_2=\frac{1}{2}\cdot (3M)\cdot (\frac{v}{3})^2=\frac{3}{18}Mv^2

loss of Energy=K_1-K_2

=\frac{3}{2}Mv^2-\frac{3}{18}Mv^2

=\frac{4}{3}Mv^2

                   

3 0
3 years ago
A stiff wire 50.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
zloy xaker [14]

Answer:

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

Explanation:

The stiff wire 50.0cm long bent at a right angle in the middle

One section lies along the z axis and the other is along the line y=2x in the xy plane

\frac{y}{x} = 2

tan θ = 2

Therefore,

slope m = tan θ = y / x

\theta=\tan^-^1(2)=63.4^0

Then length of each section is 25.0cm

so, length vector of the wire is

\hat I= (-25.0)\hat k +(25.0) \cos 63.4^0 \hati +(25.0) \sin63.4^0 \hatJ\\\\\hat I = (11.2) \hat i + (22.4) \hat j - (23.0) \hat k

And magnetic field is B = (0.318T)i

Therefore,

\bar F = \hat I (\bar l \times \bar B)

\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]

= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k

Magnitude of the force is

F = \sqrt{(-1.59N)^2+(-1.425N)^2\\} \\F = 2.135N

Direction is

\alpha = \tan^-^1(\frac{-1.425N}{-1.59N} )\\\\= 41.8^0

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

5 0
3 years ago
Read 2 more answers
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