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timofeeve [1]
3 years ago
9

Is the gravitational force between the two objects attractive, repelling, or both? Explain how you know

Physics
1 answer:
puteri [66]3 years ago
6 0

Answer: attractive

Explanation:

According to Newton's law of Gravitation, the gravitational force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}  

Where:

G is the Gravitational Constant

m1 and m2 are the masses of the objects

r  is the distance between the objects

It should be noted: this force is a central force and is attractive.

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kipiarov [429]

Answer:

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5 0
2 years ago
Which muscle group works the hardest (isometrically) when performing a wrist curl in the pronated position?
Elenna [48]
Hello!
I believe its A. wrist flexors but im not exactly sure because it might be B. wrist extensors.
6 0
3 years ago
Read 2 more answers
How does the configuration of the electric field occur between a "parallel plate" setup in a lab?What is the effect of conductor
sleet_krkn [62]

Explanation:

The magnitude of the electric field between the plates is given by

E = -ΔV/d

minus sign indicates Potential decreases in the direction of electric field

where

ΔV is the potential difference between the plates

D is the distance between the plates.

The work done when carrying an electrical charge on an equipotential surface between one position to the other is zero W= q(V-V)=0 The electric field lines of force are always perpendicular to an equipotential surface.  That conductor in an equipotential surface as direction E is at right angles to an eauipotential surface The intensity of the electric field along an equipotential surface is always zero. Equipotential surfaces never collide with each other as this would mean that at that point, there are two alternative values that are not true.

8 0
2 years ago
What is 6,210 bucks converted to kilobucks?
Vinvika [58]

When 6210 bucks is converted to kilobucks, the result obtained is  6.21 kilobucks

<h3>Conversion scale </h3>

1000 bucks = 1 Kilobuck

Using the above convesion scale, we can express 6210 bucks in kilobucks

<h3>How to express bucks in kilobucks</h3>

1000 bucks = 1 Kilobuck

Therefore,

6210 bucks = (6210 × 1) / 1000

6210 bucks = 6.21 kilobucks

Thus, 6210 bucks is equivalent to 6.21 kilobucks

Learn more about conversion:

brainly.com/question/2139943

4 0
2 years ago
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A car is moving with an initial relocity of
MA_775_DIABLO [31]

Answer:

The final acceleration of the car, v = 70 m/s

Explanation:

Given,

The initial velocity of the car, u = 20 m/s

The acceleration of the car, a = 10 m/s²

The time period of travel, t = 5 s

Using the I equations of motion

                     v = u + at

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                        = 20 + 50

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Hence, the final acceleration of the car, v = 70 m/s

4 0
2 years ago
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