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3 years ago

Is the gravitational force between the two objects attractive, repelling, or both? Explain how you know

Physics

1 answer:

puteri [66]3 years ago

6 0

Answer: attractive

Explanation:

According to Newton's law of Gravitation, the gravitational force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$

Where:

$G$ is the Gravitational Constant

$m1$ and $m2$ are the masses of the objects

$r$ is the distance between the objects

It should be noted: this force is a central force and is attractive.

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Answer:

The tension to bring the guitar string into tune is 372.95 Hz.

Explanation:

Given;

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The tension on the string to bring the guitar string into tune is calculated as;

$v = \sqrt{\frac{T}{\mu} } \\\\f\lambda = \sqrt{\frac{T}{\mu} } \\\\f^2\lambda^2 = \frac{T}{\mu} \\\\f^2 = \frac{T}{\mu \lambda^2}\\\\let \ {\mu \lambda^2} = k\\\\f^2 =\frac{T}{k} \\\\k = \frac{T}{f^2} \\\\\frac{T_1}{f_1^2} = \frac{T_2}{f_2^2}\\\\T_2 = \frac{T_1 f_2^2}{f_1^2} \\\\T_2 = \frac{350 \times 256^2}{248^2} \\\\T_2 = 372.95 \ Hz$

Therefore, the tension to bring the guitar string into tune is 372.95 Hz.

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3 years ago

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The correct choice would be

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