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NeX [460]
3 years ago
12

3. A bird flying 4 m/s has 8 joules of kinetic energy. What is the mass of the bird?

Physics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

The mass of the bird is 1 [kg]

Explanation:

The kinetic energy is defined by the following equation:

E_{k} =\frac{1}{2} *m*v^{2}\\

where:

m= mass of the bird [kg]

v = velocity of the bird [m/s]

Ek = kinetic energy [J]

We need to clear the mass from the equation given.

m=\frac{2*E_{k} }{v^{2}} \\m=\frac{2*8}{(4)^{2} } \\m=1 [kg]

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3 m/s north is an example of a(n) ____.
alexandr1967 [171]
Rate of speed (3 m/s north is three miles per second north, so it's a rate of speed)
4 0
3 years ago
Read 2 more answers
You plan to take your hair blower to europe, where the electrical outlets put out 240 v instead of the 120 v seen in the united
Eddi Din [679]
P = U × I
I = P / U = 1600W / 120V = 13.4A
P = 240V × 13.4A = 3216W

If your hair blower isnt rated for 220- 230V(this is the voltage in EU) you are most likely going to burn it.
3 0
3 years ago
A 50.-kilogram rock rolls off the edge of a cliff. if it is traveling at a speed of 24.2 m/s when it hits the ground, what is th
ElenaW [278]

The correct answer to the question is : 29.88 m.

EXPLANATION :

As per the question, the mass of the rock m = 50 Kg.

The rock is rolling off the edges of the cliff.

The final velocity of the rock when it hits the ground v = 24 .2 m/s.

Let the height of the cliff is h.

The potential energy gained by the rock at the top of the cliff = mgh.

Here, g is known as acceleration due to gravity, and g = 9.8\ m/s^2

When the rock rolls off the edge of the cliff, the potential energy is converted into kinetic energy.

When the rock hits the ground, whole of its potential energy is converted into its kinetic energy.

The kinetic energy of the rock when it touches the ground is given as -

                Kinetic energy K.E = \frac{1}{2}mv^2.

From above we know that -

   Kinetic energy at the bottom of the cliff = potential energy at a height h

                 \frac{1}{2}mv^2=\ mgh

                ⇒ v^2=\ 2gh

                ⇒ h=\ \frac{v^2}{2g}

                ⇒ h=\ \frac{(24.2)^2}{2\times 9.8}

                ⇒ h=\ 29.88\ m

Hence, the height of the cliff is 29.88 m

             


5 0
3 years ago
describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.

Pluck any string.  Then, slightly twist the tuning peg for that string,
and pluck the string again.

Twisting the peg only changed the string's tension; the length
couldn't change.

-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.

-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
3 0
3 years ago
Suppose you receive $15.00 at the beginning of a week and spend $2.50 each day for lunch. You prepare a graph of the amount you
cestrela7 [59]

Answer:

positive or zero

Explanation:

if you say the amount can be accumulated, then the slope should be positive

if the amount can't be accumulated , the slope should be zero

8 0
3 years ago
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