Answer:
Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g.
Explanation:
Part B:
The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below
calculate the moles of C4H10 used = mass/molar mass
moles = 4.86g/58 g/mol =0.0838 moles
write a balanced equation for reaction
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
by use of mole ratio between C4H10 to H2O which is 2:10 the moles of
H20= 0.0838 x10/2 = 0.419 moles of H2O
mass = moles x molar mass
=0.419 molx 18 g/mol = 7.542 grams of water is formed
Citric acid
Ethanoic acid
Methanoic acid
Lactic acid
Answer: Ecosystem services are the flows of benefits which people gain from natural ecosystems, and natural capital is the stock of natural ecosystems from which these benefits flow. So, a forest is a component of natural capital, while climate regulation or timber might be the ecosystem service it provides.
<span>we know that each
element has an unique spectra and it can be used to identify the
element. it shows that the energy levels of the electrons and different colors are the result of different wavelengths.
hope it helps
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Answer:
141.0 g NaN₃.
Explanation:
It is a stichiometric problem.
Firstly, we should wright the reaction as a balanced equation:
2NaN₃ → 2Na + 3N₂
It is clear that 2.0 moles of NaN₃ decompose to 2.0 mole of Na and 3.0 moles of N₂.
Then we should convert the volume of N₂ (70.0 L) to moles via using the gas law of ideal gas: PV = nRT, n = PV / RT,
Where, P is the pressure of the gas in atm (P = 1.2 atm).
V is the volume of the gas in L(V = 70.0 L).
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature in K(T = 315 K).
∴ n of N₂ = PV / RT = (1.2 atm) (70.0 L) / (0.082 L.atm/mol.K) (315 K) = 3.252 mole.
From the stichiometry:
2.0 moles of NaN₃ decomposes to → 3.0 moles of N₂
??? mole of NaN₃ decomposes to → 3.2520 moles of N₂
The number of moles of NaN₃ = (2.0 moles of NaN₃) (3.2520 moles of N₂) / (3.0 moles of N₂) = 2.168 mole.
Finally, we can convert the number of moles of NaN₃ to mass using the relation: m = n x molar mass.
Molar mass of NaN₃ = 65.0 g/mol.
the mass of NaN₃ = n x molar mass = (2.168 mole) (65.0 g/mol) = 140.92 g ≅ 141.0 g.