Answer:
That iron atom is oxidized. It loses two electrons.
Explanation:
Compare the formula of an iron atom and an iron(II) ion:
- Iron atom:  ; ;
- Iron(II) ion:  . .
The superscript  in the iron(II) ion is the only difference between the two formulas. This superscript indicates a charge of
 in the iron(II) ion is the only difference between the two formulas. This superscript indicates a charge of  on each ion. Atoms and ions contain protons. In many cases, they also contain electrons. Each proton carries a positive charge of
 on each ion. Atoms and ions contain protons. In many cases, they also contain electrons. Each proton carries a positive charge of  and each electron carries a charge of
 and each electron carries a charge of  . Atoms are neutral for they contain an equal number of protons and electrons.
. Atoms are neutral for they contain an equal number of protons and electrons. 
Protons are located at the center of atoms inside the nuclei. They cannot be gained or lost in chemical reactions. However, electrons are outside the nuclei and can be gained or lost. When an atom loses one or more electrons, it will carry more positive charge than negative charge. It will becomes a positive ion. Conversely, when an atom gains one or more electrons, it becomes a negative ion.
An iron atom  will need to lose two electrons to become a positive iron(II) ion
 will need to lose two electrons to become a positive iron(II) ion  with a charge of
 with a charge of  on each ion. That is:
 on each ion. That is:
 .
.
- Oxidation is Losing one or more electrons;
- Reduction is Gaining one or more electrons.
This definition can be written as the acronym OILRIG. (Khan Academy.)
In this case, each iron atom loses two electrons. Therefore the iron atoms here are oxidized.
 
        
             
        
        
        
It is a solid in its natural state but it can be a liquid
        
             
        
        
        
In an exothermic reaction, heat is transferred to the surrounding. 
Hope this helps, have a great day ahead!
        
                    
             
        
        
        
Cu+ p=29 e=28 n=34 
S2- p=16 e=18 n=16
Pb4+ p=82 e=78 p=125 
I hope i did it right :))