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devlian [24]
3 years ago
9

What product is formed when 1-bromopropane reacts with ch3o−?

Chemistry
1 answer:
STatiana [176]3 years ago
4 0
When 1-Bromopropane is treated with methoxide it undergoes SN² Reaction. The product formed is Methyl Propyl Ether. This type of reaction is very important in synthesizing Asymmetric ethers. The alkoxides are oftenly generated by reacting Alcohols with sodium metal, which on elimination of Hydrogen gas produces corresponding alkoxide. The reaction of given statement is as follow,

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Which of the following sequences describe how a four stoke engine cycle powers the engine
Vera_Pavlovna [14]

A four cycle engine works with 4 basic steps to a successful rotation of the crankshaft: the intake, compression, power and exhaust stroke. Each engine cylinder has four openings for the intake, exhaust, spark plug and fuel injection. ... The compression makes the air-fuel combination volatile for easier ignition.

8 0
3 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
A solution is prepared by adding 1.43 mol of kcl to 889 g of water. the concentration of kcl is ________ molal. a solution is pr
s344n2d4d5 [400]
A solution is prepared by adding 1.43 mol of potassium chloride (kcl) to 889 g of water. The concentration of kcl is 1.61  molal.
mol of Kcl (potassium chloride)= 1.43
water = 889 g
the formula for calculating molality is:
molality = moles of solute/kilograms of solvent
1kg = 1000g so, 889g = 0.889kg

m = 1.43/0.889 = 1.61 molal
7 0
2 years ago
One example of an ionic compound is<br><br> F2 <br> CO2<br> HBr<br> MgCL2
allochka39001 [22]
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
7 0
3 years ago
Read 2 more answers
Consider the reaction: NO2(g) + CO(g) ⇌ NO(g) + CO2(g) Kc = 0.30 at some temperature. If the initial mixture has the concentrati
Stolb23 [73]

This is an incomplete question, here is a complete question.

Consider the reaction: NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

Kc = 0.30 at some temperature.

If the initial mixture has the concentrations below, the system is_______.

Chemicals   Concentration (mol/L)

- NO₂            0.024

- CO               0.360

- NO               0.180

- CO₂             0.120

Possible answers:

1) not at equilibrium and will remain in an unequilibrated state.

2) not at equilibrium and will shift to the left to achieve an equilibrium state.

3) not at equilibrium and will shift to the right to achieve an equilibrium state.

4) at equilibrium

Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Explanation:

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

First we have to determine the value of reaction quotient (Qc).

The given balanced chemical reaction is,

NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

The expression for reaction quotient will be :

Q_c=\frac{[NO][CO_2]}{[NO_2][CO]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q_c=\frac{(0.180)\times (0.120)}{(0.024)\times (0.360)}=2.5

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K that means product = reactant. So, the reaction is in equilibrium.

The given equilibrium constant value is, K_c=0.30

From the above we conclude that, the Q>K that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.

Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

8 0
3 years ago
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