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aleksklad [387]
3 years ago
15

During meiosis, only one chromosome from each homologous is passed on to the offspring. What does this help increase?

Chemistry
1 answer:
Helga [31]3 years ago
6 0
This helps increase variation in the offspring.
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Draw a structure showing an aromatic resonance form. Include formal charges and lone pair electrons on the oxygen atom.
ryzh [129]

Answer:

answer is attached

Explanation:

Benzene is a common organic solvent that was previously used in gasoline; it is no longer used for this purpose, however, because it is now known to be a carcinogen. The benzene molecule (C6H6C6H6) consists of a regular hexagon of carbon atoms, each of which is also bonded to a hydrogen atom. Use resonance structures to describe the bonding in benzene.

Given: molecular formula and molecular geometry

Asked for: resonance structures

Strategy:

Draw a structure for benzene illustrating the bonded atoms. Then calculate the number of valence electrons used in this drawing.

Subtract this number from the total number of valence electrons in benzene and then locate the remaining electrons such that each atom in the structure reaches an octet.

Draw the resonance structures for benzene.

Solution:

A Each hydrogen atom contributes 1 valence electron, and each carbon atom contributes 4 valence electrons, for a total of (6 × 1) + (6 × 4) = 30 valence electrons. If we place a single bonding electron pair between each pair of carbon atoms and between each carbon and a hydrogen atom, we obtain the following:

Each carbon atom in this structure has only 6 electrons and has a formal charge of +1, but we have used only 24 of the 30 valence electrons.

B If the 6 remaining electrons are uniformly distributed pairwise on alternate carbon atoms, we obtain the following:

Three carbon atoms now have an octet configuration and a formal charge of −1, while three carbon atoms have only 6 electrons and a formal charge of +1. We can convert each lone pair to a bonding electron pair, which gives each atom an octet of electrons and a formal charge of 0, by making three C=C double bonds.

C There are, however, two ways to do this:

Each structure has alternating double and single bonds, but experimentation shows that each carbon–carbon bond in benzene is identical, with bond lengths (139.9 pm) intermediate between those typically found for a C–C single bond (154 pm) and a C=C double bond (134 pm). We can describe the bonding in benzene using the two resonance structures, but the actual electronic structure is an average of the two. The existence of multiple resonance structures for aromatic hydrocarbons like benzene is often indicated by drawing either a circle or dashed lines inside the hexagon:

7 0
3 years ago
An unknown substance is made only of identical atoms that cannot be broken down. This substance is a ________.
Veseljchak [2.6K]
The substance is an element off of the periodic table. 
7 0
3 years ago
Read 2 more answers
How many moles of air must escape from a 10-m  8.0-m  5.0-m room when the temperature is raised from 0c to 20c? assume the p
slega [8]
Data:

p = 1 atm
V = 10 m * 8 m * 5 m = 400 m^3 = 400,000 liter

To = 0 + 273.15K = 273.15K
Tf = 20 + 273.15K = 293.15K

No - Nf =?

2) Formula

pV = NRT => N = pV / (RT)

3) solution

No = pV / (RTo)

Nf = pV / (RTf)

=> No - Nf = [pv / R] [ 1 / To - 1 / Tf ]

=> No - Nf = [1atm*400,000liter / 0.0821 atm*liter/K*mol ] [ 1 / 273.15 - 1 / 293.15]

No - Nf = 1216.9 moles ≈ 1217 moles

Answer: 1217 moles
3 0
3 years ago
in which level of organization would the roots of a plant most likely be classified? Please explain too
abruzzese [7]

Kaka ml nyu yan wala kaming paki kung ano ang lagi ginagawa nyu

8 0
3 years ago
Calculate the pH for the following solutions and indicate whether each solution is acidic or basic.
Nadya [2.5K]
The answer would for sure be 178 because acid & base make that amount so yea!! I’m talllyyy right
6 0
2 years ago
Read 2 more answers
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