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777dan777 [17]
4 years ago
6

For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a length L1 the pressure drop over the

length is p1. If the length of the pipe is then doubled, what is the relation of the new pressure drop p2 to the original pressure drop p1 at the original mass flow rate?
Physics
1 answer:
Gnom [1K]4 years ago
5 0

Answer: ∆p2 = 2* ∆p1

Explanation:

Given that all other factors remain constant. The pressure drop across the pipeline is directly proportional to the length.

i.e ∆p ~ L

Therefore,

∆p2/L2 = ∆p1/L1

Since L2 = 2 * L1

∆p2/2*L1 = ∆p1/L1

Eliminating L1 we have,

∆p2/2 = ∆p1

Multiplying both sides by 2

∆p2 = 2 * ∆p1

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W=m/d. w=51.7\1.20 W=43.083333333J
6 0
2 years ago
A brick is dropped from a big scaffold. What is its velocity after 4.0s?
Flura [38]

The velocity of the brick is 39.2 m/s downward

Explanation:

The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of g=9.8 m/s^2.

So, we can find its velocity using the suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the brick in this problem (taking downward as positive direction)

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2

Therefore, its velocity after t = 4.0 s is:

v=0+(9.8)(4.0)=39.2 m/s

Downward, because the sign is positive.

Learn more about free fall motion:

brainly.com/question/1748290

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#LearnwithBrainly

3 0
3 years ago
A bike travels at a constant speed of 3.1 m/s for 6 s. how far does it go?
IgorC [24]
Ah for this problem you are thinking quite a bit hard on. The problem is actually simpler than it looks. The problem states that a bike travels at a constant speed of 3.1 m/s for 6 s and asks how far will it go?. To figure this out you simply need to take 3.1 times 6 s because every second the bike travels 3.1 m. So the answer to this problem would be 18.6 m
8 0
4 years ago
When 23Na is bombarded with protons, the products are 20Ne and A. a neutron B. an alpha particle C. a deuteron D. a gamma ray pa
Vikki [24]

Answer:

The correct option is B. an alpha particle.

Explanation:

When ²³Na is bombarded with protons _{1}^{1}\textrm{H}, ²⁰Ne and one alpha particle _{2}^{4}\textrm{He} is released.

The reaction is as follows:

_{11}^{23}\textrm{Na} + _{1}^{1}\textrm{H} \rightarrow _{10}^{20}\textrm{Ne} + _{2}^{4}\textrm{He}

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.

5 0
4 years ago
Wavelength is measured in hertz true or false?
g100num [7]
Wavelength is measured in various units of distance (mm, cm, m, etc.). Frequency uses hertz, but that is not what the question is asking. Therefore, the answer is false.
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3 years ago
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