Answer:
final kinetic energy of the hammer is 10 kJ
Explanation:
As we know that there is no non conservative force on the system
So here we can use the theory of mechanical energy conservation
So we will have
here we know that
from above expression now
so final kinetic energy of the hammer is 10 kJ
Coulomb's Law
Given:
F = 3.0 x 10^-3 Newton
d = 6.0 x 10^2 meters
Q1 = 3.3x 10^-8 Coulombs
k = 9.0 x 10^9 Newton*m^2/Coulombs^2
Required:
Q2 =?
Formula:
F = k • Q1 • Q2 / d²
Solution:
So, to solve for Q2
Q2 = F • d²/ k • Q1
Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9
Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)
Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)
Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)
Then, take the reciprocal of the denominator and start
multiplying
Q2 = 1080 • 1 Coulombs/297
Q2 = 1080 Coulombs / 297
Q2 = 3.63636363636 Coulombs
Q2 = 3.64 Coulumbs
Answer:
The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.
Explanation:
Weight of the object on the surface of Earth, W = 245 N
On the surface of Earth, acceleration due to gravity, g = 10 m/s²
Weight of an object is given by :
W = mg
m is mass
So, the mass of the object is 24.5 kg
Acceleration due to gravity on Mars, g' = 3.72 m/s²
Weight of the object on Mars,
W' =mg'
W' = 24.5 kg × 3.72 m/s²
= 91.14 N
So, the weight of the object on Mars is 91.14 N.
Answer:
Transverse wave and Longitudinal wave and Electromagnetic wave
Explanation:
- An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
- Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
- Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
- Most electromagnetic waves are transverse in nature.
The current that would pass through the 30 ohms resistor is 2 A.
<h3>What is electric current?</h3>
Electric current is the rate of flow of electric charge round a conductor.
To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below
Formula:
- I = V/Rt........... Equation 1
Where:
- I = Electric current passing through the 30 ohms resistor
- V = Voltage
- Rt = Total or effective resistance of the resistors.
From the question,
Given:
- V = 100 volts
- Rt = (30+20) ohms (since both resistors are connected in series)
Substitute these values into equation 1
Hence, The current that would pass through the 30 ohms resistor is 2 A.
Learn more about electric current here: brainly.com/question/1100341
