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2 years ago

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Explanation: One can pick up a nail using the curved part of the horseshoe magnet farthest from the poles. A horse shoe magnet h

as magnetic fields all around it. In the presence of magnetic force fields, any magnetic object will be attracted to it.

1 answer:

PIT_PIT [208]2 years ago

4 0

Answer:

is there anymore choices than A

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Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0*109 V and the quantity of charg

nata0808 [166]

Answer:

a) $U_{e} = 3 \times 10^{10}\,J$ , b) $v \approx 7745.967\,\frac{m}{s}$

Explanation:

a) The potential energy is:

$U_{e} = Q \cdot \Delta V$

$U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)$

$U_{e} = 3 \times 10^{10}\,J$

b) Maximum final speed:

$U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }$

The final speed is:

$v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }$

$v \approx 7745.967\,\frac{m}{s}$

3 0

2 years ago

A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between

gladu [14]

Hi there!

The period of an orbit can be found by:

$T = \frac{2\pi r}{v}$

T = Period (? s)
r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

$T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}$

8 0

1 year ago

Most earthquakes happen:

umka2103 [35]

Along plate edges, at points where oceanic or continental plates meet ot at the edges of the plates

4 0

2 years ago

Read 2 more answers

What if an object traveled from position -6 m to -1 m, what is the distance traveled?

Oxana [17]

The object traveled +5 m

4 0

2 years ago

Read 2 more answers

What is the direction of a vector with an x component of -12 m and a y component of -15 m?

dusya [7]

Answer:

$51.34^{\circ}$

Explanation:

Given that,

x component of a vector = -12 m

The y component of a vector = -15 m

We need to find the direction of a vector. The direction of a vector is given by :

$\tan\theta=\dfrac{y}{x}$

Put all the values,

$\tan\theta=\dfrac{-15}{-12}\\\\\theta=\tan^{-1}(\dfrac{-15}{-12})\\\\\theta=51.34^{\circ}$

So, the direction of vector is $51.34^{\circ}$ to x component.

3 0

2 years ago