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3 years ago

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Explanation: One can pick up a nail using the curved part of the horseshoe magnet farthest from the poles. A horse shoe magnet h

as magnetic fields all around it. In the presence of magnetic force fields, any magnetic object will be attracted to it.

1 answer:

PIT_PIT [208]3 years ago

4 0

Answer:

is there anymore choices than A

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8. A car starts from rest and accelerates at 5.5ms in an easterly direction.

snow_lady [41]

Initial velocity=0m/s=u
Acceleration=a=5.5m/s^2

#8.1

t=12s

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+5.5(12)$

$\\ \sf\longmapsto v=66m/s$

#8.2

u=0m/s
v=18m/s
a=5.5m/s^2

Use third equation of kinematics

$\\ \sf\longmapsto v^2-u^2=2as$

$\\ \sf\longmapsto s=\dfrac{v^2-u^2}{2a}$

$\\ \sf\longmapsto s=\dfrac{18^2-0^2}{2(5.5)}$

$\\ \sf\longmapsto s=\dfrac{324}{11}$

$\\ \sf\longmapsto s=29.4m$

8 0

3 years ago

Read 2 more answers

What is the scientific definition of tracked?

dexar [7]

To find or discover by investigation?

8 0

3 years ago

The lesser the mass, the greater the acceleration for the given value of force. Why does this happen?

Tju [1.3M]

Newtons law states F=ma
so F/m=a
in addition it makes logical sense the lighter an object the easier it is to accelerate its velocity form 0 to some quantity

5 0

3 years ago

What is the electric potential energy of a charge that experiences a force of 3.6x10^-4 N when it is 9.8x10^-5 m from the source

jekas [21]

<u>Answer:</u>

3.5 x 10^-8 J

<u>Explanation:</u>

We are given,

force experienced by a charge = 3.6 x 10^-4 N; and

distance of charge from the source of electric field = 9.8 x 10^-5 m

We know that, <em>Energy = force x distance</em>

therefore, to find the potential energy of the charge, we need to multiply its applied force with the given distance to get:

Electric potential energy of a charge = (3.6 x 10^-4) × (9.8 x 10^-5) = 3.5 x 10^-8 J

Therefore, the potential energy of a charge is 3.5 x 10^-8 J.

6 0

4 years ago

Which water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B prot

sergiy2304 [10]

Answer:

10 cm

Explanation:

water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection is 10 cm . the bar graph attached in the shows that the lengths of yellow and brown bars differ the most at 10 cm.

Hence,The biggest difference between the survival rates of UV-B protected and unprotected can be seen at the depth of 10 cm.

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3 years ago