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lora16 [44]
3 years ago
13

Explanation: One can pick up a nail using the curved part of the horseshoe magnet farthest from the poles. A horse shoe magnet h

as magnetic fields all around it. In the presence of magnetic force fields, any magnetic object will be attracted to it.
Physics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

is there anymore choices than A

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Which of the following has the least amount of kinetic energy?
alexandr1967 [171]

Answer:

a 10 kg elephant moving at 1 m/s

Explanation:

because kinetic energy depend on how fast an object moves and also depend on the gravitational force which include the weight.

8 0
3 years ago
During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the
natita [175]

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

4 0
3 years ago
How many types of quarks are there?<br> a. 2<br> b. 4<br> c. 6<br> d. 8
Nostrana [21]
There are 6 types of quarks.

Answer: C. 6
8 0
3 years ago
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A cart with a mass of 0.5 kg is at the top of the ramp. The height is 0.40m .
Tju [1.3M]

A=0.05.0M.

B=68.9244GPE.34

C=0

D it would be 79%HIGHER

3 0
3 years ago
A toroidal coil of N turns has a central radius b and a square cross section of side a. Find its self-inductance.
Xelga [282]

Answer:

L = \frac{\mu_0 N^2 (a^2)}{2\pi b}

Explanation:

As we know that magnetic field due to torroid is given as

B = \frac{\mu_0 N i}{2\pi b}

this is approximately constant magnetic field along the axis of the torroid

now the flux linked with one coil of the torroid is given as

\phi = B.A

\phi = \frac{\mu_0 N i}{2\pi b}(a^2)

now total flux of N number of coils is given as

\phi_{total} = \frac{\mu_0 N^2 i(a^2)}{2\pi b}

now we know that self inductance is the property of coil in which flux of the coil will link with the current in the coil

So we know that

L = \frac{\phi}{i}

L = \frac{\mu_0 N^2 (a^2)}{2\pi b}

3 0
3 years ago
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