Question

A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What will be the new pressure?

Answer 1

The answer for the following question is answered below.

• Therefore the new pressure of the gas is 1.76 atm.

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    P ∝ T

     $\frac{P}{T}$ = constant  

     $\frac{P_{1} }{P_{2} }$ = $\frac{T_{1} }{T_{2} }$

Where;

$P_{1}$ = initial pressure of a gas

$P_{2}$ = final pressure of a gas

$T_{1}$ = initial temperature of a gas

$T_{2}$ = final temperature of  a gas

    $P_{2}$ = $\frac{1.34*312}{237}$

    $P_{2}$  = 1.76 atm

Therefore the new pressure of the gas is 1.76 atm.