I truly believe so, that’s a definite yes
Answer:
option C
Explanation:
given,
Force on the object = 10 N
distance of push = 5 m
Work done = ?
we know,
work done is equal to Force into displacement.
W = F . s
W = 10 x 5
W = 50 J
Work done by the object when 10 N force is applied is equal to 50 J
Hence, the correct answer is option C
Answer:
it would be least to graetest
Explanation:
10-84
Answer:
F = 800N
the magnitude of the average force exerted on the wall by the ball is 800N
Explanation:
Applying the impulse-momentum equation;
Impulse = change in momentum
Ft = m∆v
F = (m∆v)/t
Where;
F = force
t = time
m = mass
∆v = v2 - v1 = change in velocity
Given;
m = 0.80 kg
t = 0.050 s
The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed.
v2 = 25 m/s
v1 = -25 m/s
∆v = v2 - v1 = 25 - (-25) m/s = 25 +25 = 50 m/s
Substituting the values;
F = (m∆v)/t
F = (0.80×50)/0.05
F = 800N
the magnitude of the average force exerted on the wall by the ball is 800N
Answer:
F = 592238.09 N
Explanation:
To find the mean force you first calculate the acceleration by using the following kinematic equation:
you do "a" the subject of the equation and replace the values of the other parameters:
next, the force, by using the second Newton law is:
hence, the force is 592238.09 N
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TRANSLATION:
Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:
você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:
Em seguida, a força, usando a segunda lei de Newton, é:
portanto, a força é 592238.09 N
