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Vadim26 [7]
3 years ago
10

Please need help on this

Physics
2 answers:
exis [7]3 years ago
8 0
80 degrees Celsius is the correct answer.
Nookie1986 [14]3 years ago
5 0
The answer is c) 80°c
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John and Caroline go out for a walk one day. This graph represents their distance from home.
Serga [27]

Answer:

Option C is the correct answer.

Explanation:

  We have velocity of a body = Change in position/ Time.

  Considering first portion of graph,

  Change in position = 30 - 0 = 30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = 30/2700 = 0.011 m/s

  Considering second portion of graph,

  Change in position = 30 - 30 = 0 m

  Time = 0.5 hours = 30 minutes = 1800 seconds

   Velocity = 0/1800 = 0 m/s

 Considering third portion of graph,

  Change in position = 0 - 30 = -30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = -30/2700 = -0.011 m/s

So firstly they walked in one direction(positive direction), then they were still(velocity is zero), then they walked in the opposite direction( velocity is negative).

Option C is the correct answer.

3 0
3 years ago
Read 2 more answers
You push a cart with mass 15 kg forward , giving it an acceleration of 3 m/s ^ 2 . How much force did you apply ? O A. 0.2N O B.
Alexandra [31]

Answer: force = mass x accelegation

Explanation: 15x3 = 45 N

7 0
2 years ago
Read 2 more answers
Two blocks are connected by a massless cable which goes through the center of a rotating turntable. The blocks have masses M1 =
Airida [17]

Answer:

If the final question is; at what velocity will the first block start to move outward in m/s?

v = 3.5596 \frac{m}{s}

Explanation:

The motion have the velocity that will make the block move using:

F_{1}*F_{r}+ F_{2}= Ec \\Ec= \frac{M*v^{2} }{r}

m_{1} = 1.2 Kg

m_{2} = 2.8 Kg

r = 0,45 m

μs= 0,54

Resolving:

\frac{m_{1}*v^{2}  }{r} = us*m_{1}* g + m_{2} * g

v^{2} = \frac{((us *m_{1} + m_{2})*g )* r}{m_{1} }

v^{2} = \frac{((0.54 *1.2 + 2.8)*9.8 )* 0.45}{1.2}

v^{2} = 12.6714 \frac{m^{2} }{s^{2} }

v = 3.559 \frac{m}{s}

4 0
3 years ago
what consistent physiological pattern are more common in women's teeth? A. Women's canines are generally sharper. B. Women have
irakobra [83]

Answer:

B

Explanation:

B. Women have straighter teeth.

5 0
3 years ago
A rocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. It moves for 7 s along its initial
vagabundo [1.1K]

Answer:

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

a=19 \frac{m}{s^{2} } \\voy=vo*sin(\alpha )\\voy=90*sin(39 )\\y_{o}=0m\\y_{f}=y_{o}+v_{oy}*t+\frac{1}{2}*a*t^{2}\\y_{f}=90*sin(39)*7s+\frac{1}{2}*19\frac{m}{s^{2} }*(7)^{2}\\y_{f}=861.97m

Now the motion the rocket moves as a projectile so:

v_{fy}=v_{iy}+a*t\\v_{fy}=90+9.8*7\\v_{fy}=158.6 sin(39)

Now the final velocity is the initial in the second one

v_{fy}^{2}=v_{fi}^{2}+2*a*yf \\\\a=g\\

The maximum altitude Vf=0

0=v_{fi}^{2}+2*a*yf \\\\yf=\frac{(158.6 sin(39))^{2} }{2*9.8\frac{m}{s^{2} } } \\yf=508.26m

So total altitude is both altitude of the motion so:

Y=508.2m+861.97m\\Y=1370.23m

6 0
3 years ago
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