Ask question

Ask question

All categories

4 years ago

5

what consistent physiological pattern are more common in women's teeth? A. Women's canines are generally sharper. B. Women have

straighter teeth. C. Women have 1 less set of molar teeth. D. Women normally have longer pre-molars.

1 answer:

irakobra [83]4 years ago

5 0

Answer:

B

Explanation:

B. Women have straighter teeth.

You might be interested in

given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone brid

dalvyx [7]

Answer:

The balanced condition for Wheat stones bridge is

Q

P

=

S

R

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R

1

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R

2

=R+S

=20+30=50Ω

Net resistance of the network as R

1

and R

2

are in parallel

i=

R

V

=

50

6×3

=0.36 A.

Explanation:

8 0

3 years ago

what will be the effect on the acceleration due to gravity of the earth if it is compressed to a the size the moon?

GuDViN [60]

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

7 0

3 years ago

Read 2 more answers

1. A vector is given by its components, Ax = 2.5 and A, = 7.5. What angle

Allushta [10]

Answer:

A) 72° or 71.56°

Explanation:

We have two components on the X-axis and y-axis respectively. So we can use the tangent of the angle to be able to find the angle with respect to the horizontal component.

Ax = 2.5

Ay = 7.5

tan(α) = 7.5/2.5

$\alpha = tan^{-1} (3)\\$

α = 71.56°

4 0

3 years ago

What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?

lisov135 [29]

Answer:

Wavelength of sound in the pipe is 6.0 m

Explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have

$L = \frac{\lambda}{4} + \frac{\lambda}{2}$

where L = length of the pipe

so we have

$4.5 = \frac{3\lambda}{4}$

$\lambda = 6.0 m$

5 0

3 years ago

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i

Virty [35]

Answer:

<em>J=600 kg m/s </em>

Explanation:

<u>Impulse And Momentum </u>

Suppose a particle is moving at a certain speed $v_1$ and changes it to $v_2$ . The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

$p=mv$

The initial and final momentums are given, respectively, by:

$p_1=mv_1,\ p_2=mv_2$

Thus, the change of momentum is

$\Delta p=p_2-p_1=m(v_2-v_1)$

It's equal to the Impulse J

$J=\Delta p$

$J=m(v_2-v_1)$

Our data is

$m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s$

$J=50\ (17-5)$

$J=600\ kg\ m/s$

7 0

3 years ago