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3 years ago

7

Nora stirs one teaspoon, about 4.2 g, of sugar into her mug, which holds about 0.25 L of tea. What is the concentration of sugar

in Nora’s tea?

1 answer:

Reptile [31]3 years ago

7 0

Answer:

16.8 g/L.

Explanation:

Given that,

Mass of sugar, m = 4.2 g

Volume of tea, V = 0.25 L

We need to find the concentration of sugar in Nora's tea.

Here, 4.2 g is the mass of solute and 0.25 L is volume of the solution.

We know that,

$\text{Mass concentration}=\dfrac{\text{Mass of solute}}{\text{Volume of solution}}\\\\C=\dfrac{4.2\ g}{0.25\ L}\\\\C=16.8\ g/L$

So, the concentration of sugar is 16.8 g/L.

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100 points+Brainliest for correct answer

morpeh [17]

Answer:

O Option 1

Explanation:

IF ENERGY IS RELEASED, THEN ENERGY RELEASED SHOULD BE SUBTRACTED FROM ORIGINAL.

(16.32 X 10^-19) - (5.4 X 10^-19)

10.92 X 10^-19

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2 years ago

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Which equation is used to help form the combined gas law?<br> eP, V, P, V, т.

alexdok [17]

Answer:

The combined gas law is formulated from PV/T =K.

Explanation:

The combined gas law comprises of Boyle's law, Charles's law and Gay lusaac's law. This laws were not discovered but simply put together considering other cases of ideal gas law. It states that if the amount of gas is left unchanged, the ratio between the pressure, volume, and temperature is constant.

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3 years ago

a compound has a molar mass of 129 g/mol if its empirical formula is C2H5N then what is the molecular formula

Elena-2011 [213]

Given :

A compound has a molar mass of 129 g/mol .

Empirical formula of compound is C₂H₅N .

To Find :

The molecular formula of the compound.

Solution :

Empirical mass of compound :

$M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + ( 1 \times 14 )\\\\M_e = 43\ gram/mol$

Now, n-factor is :

$n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3$

Multiplying each atom in the formula by 3 , we get :

Molecular Formula, C₆H₁₅N₃

3 0

2 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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3 years ago

Calculate the density of chloroform

Rina8888 [55]

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

$Density=\frac{Mass}{Volume}$

Now putting g all the given values in this formula, we get:

$Density=\frac{59.5g}{40.5mL}$

$Density=1.47g/mL$

Therefore, the density of chloroform is 1.47 g/mL

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2 years ago