Answer:
Percentage yield =58.7 %
Explanation:
moles of calcium carbonate as a reactant =
as per molar equation , 0.2068 moles of calcium carbonate produces 0.2068 moles of CaO .
amount of CaO = 0.2068 mole x (40.078+15.999) g/moles = 11.598 gram
percentage yield = actual yield / theoritical yield = 6.81/ 11.598 = 0.587 or 58.7 %
Density is mass per unit volume
2.4=8.5/v
V=8.5/2.4
V=3.54
Answer:
1) The process mentioned here is " Weathering "
2) Chemical equation =
The acid H2CO3 and the CaCO3 combine to form HCO3 + HCO3 + Ca.