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klasskru [66]
2 years ago
8

True or false The sodium atom becomes a sodium ion with a charge of +1

Chemistry
1 answer:
ddd [48]2 years ago
6 0

Answer:

True

Explanation:

The sodium atom does become a sodium ion with a charge of +1.

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Indicate whether each of the following statements is correct or incorrect.1)Every Bronsted-Lowry acid is also a Lewis acid2)Ever
Hunter-Best [27]

Answer:

1) correct

2) incorrect

3) correct

4)incorrect

Explanation:

1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.

A Bronsted-Lowry acid is a substance that donates a proton H⁺

Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.

2)A Lewis acid not necessarily needs to have a proton to be donated.

3) Conjugated acids of weak bases are strong acids and conjugated acids of strong bases are weak acids.

4)K⁺ comes from a strong base, therefore is does not have an acidic behaviour.

4 0
2 years ago
The oceanic crust is made primarily from this type of rock. A) basalt B) halite C) granite D) limestone
masya89 [10]
The answer is A. Basalt rock.

7 0
3 years ago
What is the pOH value of 0.0000877 M HCL
ki77a [65]

Answer:

pOH=9.9

Explanation:

pH=-log[H+]= -log[0.0000877]

=4.06

pOH+ pH=14

pOH=14-4.06= 9.91

7 0
3 years ago
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3rd Answer. Rays reflect in random directions
5 0
2 years ago
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A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
Mandarinka [93]
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as

pH = pKa + log [A]/[HA] 

 where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid

Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol

Solution:
pKa = - log ( 1.8x10^-5) = 4.74

[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles

pH = 4.74 + log (.115/0.085)
pH = 4.87
6 0
3 years ago
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