2 years ago

Write 4,007,500,000 in scientific notation.

Physics

1 answer:

Vika [28.1K]2 years ago

7 0

The answer is 4.0075 x 10^9

You might be interested in

Sue and jenny kick a soccer ball at exactly the same time. sue's foot exerts a force of 57.6 n to the north. jenny's foot exerts

Alika [10]

It is 17.58 my friennnd

8 0

3 years ago

The purpose of the control group is to

pogonyaev

Have everything in control and in order and discuss about different issues.

5 0

2 years ago

Read 2 more answers

Please Help!!!!! Quickly!!!! brainiest to correct answer !!!!!!

iragen [17]

Just show a picture so I can help ur information is misleading...

5 0

3 years ago

Select the correct answer.

andrew-mc [135]

I think the answer would be C

7 0

3 years ago

Read 2 more answers

An older camera has a lens with a focal length of 60mm and uses 34-mm-wide film to record its images. Using this camera, a photo

lesya692 [45]

Answer:

24.71 mm

Explanation:

Distance is proportional to focal length, so

d∝f

which means

$\frac{d'_1}{d'_2}=\frac{f_1}{f_2}$

Magnification of first lens

$M_2=-\frac{d'_1}{d_1}$

and

$M_2=\frac{h'_1}{h_1}$

Similarly, magnification of second lens

$M_2=-\frac{d'_2}{d_1}$

and

$M_2=\frac{h'_2}{h_1}$

From the above equations we get

$\frac{M_1}{M_2}=\frac{d'_1}{d_2'}$

and

$\frac{M_1}{M_2}=\frac{h'_1}{h_2'}$

which means,

$\frac{d'_1}{d_2'}=\frac{h'_1}{h_2'}$

and

$\frac{d'_1}{d_2'}=\frac{f_1}{f_2}$

So, we get

$\frac{f_1}{f_2}=\frac{h'_1}{h_2'}\\\Rightarrow f_2=f_1\times\frac{h_2'}{h'_1}\\\Rightarrow f_2=60\times\frac{14}{34}=24.71\ mm$

∴ Focal length should this camera's lens is 24.71 mm

6 0

3 years ago