Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question
Answer:
the work converted to thermal energy is 40 J.
Explanation:
Given;
work done by the physicist,w = 100 J
height through which the book is raised, h = 0.2 m
efficiency of machine = 60% = 0.6
The useful work done by the machine is calculated as;
useful work = 0.6 x 100 = 60 J
The wasted energy = 100 J - 60 J
The wasted energy = 40 J
The wasted energy by the machine is possibly converted to thermal energy by the frictional part of the machine.
Therefore, the work converted to thermal energy is 40 J.
Answer:
microscopic means that they are very very tiny, you cannot see them with the human eye, you have to use a tool like a microscope
Explanation:
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7 
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P = 
⇒ 16 = 
⇒
= 16 × 
Put the value of
we get
⇒
= 16 × 1.7
⇒
= 27.2 lb
This the total force applied during braking.
The force applied on one wheel =
=
= 6.8 lb
⇒ The force applied on one wheel during braking.
Answer:
The equatiom of kinetic energy is 1/2×m×v² where m represents mass and v is velocity :

The unit for kinetic energy is measured in Joules (J).