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3 years ago

A bird can fly at 32 km/h. How long does it take to fly 22 km?

Physics

1 answer:

Marat540 [252]3 years ago

3 0

Answer:

It takes the bird 0.6875 hour to fly 22 km

Explanation:

Lets revise the relation between the distance, speed and time

→ Distance = speed × time

→ Speed = distance ÷ time

→ Time = distance ÷ speed

A bird can fly at 32 km/h

The speed of the bird is 32 km/h

The bird will fly 22 km

We need to find the time it takes the bird to fly this distance

The speed = 32 km/h

The distance 22 km

Lets use the rule:

→ Time = distance ÷ speed

→ Time = 22 ÷ 32 = 0.6875 hour

<em>It takes the bird 0.6875 hour to fly 22 km </em>

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archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken

Cerrena [4.2K]

Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

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4 years ago

A rectangular reflecting pool is 56.5 ft wide and 141 ft long. What is the area of the pool in square meters

konstantin123 [22]

By definition, the area of the pool is 740.112 m².

<h3>Definition of area</h3>

The area is the measure of a space delimited by a contour which is called perimeter.

That is, the area gives an idea of how much surface a figure covers and is defined as the measure of the region or surface enclosed by a geometric figure.

<h3>Area of a rectangle</h3>

A rectangle is a flat geometric figure with four sides, of which two sides that are opposite parallel to each other have the same length and the remaining two have another length.

The area of a rectangle is calculated by multiplying the lengths of two contiguous sides of the figure which are different from each other, that is, the length is multiplied by the width:

Area= length× width

A rectangular reflecting pool is 56.5 ft wide and 141 ft long. So, the area of the rectangular pool is calculated as:

Area= length× width

Area= 141 ft× 56.5 ft

Solving:

<u><em>Area= 7966.5 ft²= 740.112 m²</em></u> (being 1 ft²= 0.092903 m²)

So, the area of the pool is 740.112 m².

Learn more about the area of a rectangle:

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3 years ago

There is an electric field in the region between the two plates. The magnitude of this electric field is ed. This imposes anothe

krok68 [10]

Answer:

it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

Explanation:

The configuration of parallel plates is called a capacitor and is widely used to create constant electric fields inside.

To obtain this field it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

This is so that the fields created by each plate can be added inside and subtracted from the outside of the plates

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3 years ago

Batteries are rated in terms of ampere-hours (A·h). For example, a battery that can produce a current of 2.00 A for 3.00 h is ra

Reptile [31]

(a) 423 J

The power of the battery is the ratio between the total energy stored (E) and the time elapsed (t):

$P=\frac{E}{t}$

However, the power is also the product of the voltage (V) and the current (I):

$P=VI$

Linking the two equations together,

$\frac{E}{t}=VI\\E=VIt$

Since we know:

V = 9.0 V

$I \cdot t = 47.0 A\cdot h$

We can calculate the total energy:

$E=(9.0 V)(47 A \cdot h)=423 J$

(b) $7.79\cdot 10^{-6}$ dollars

The battery has a total energy of E = 423 J. (2)

1 Watt (W) is equal to 1 Joule (J) per second (s):

$1 W = \frac{1 J}{1 s}$

so 1 kW corresponds to 1000 J/s:

$1 kW = \frac{1000 J}{1 s}$

Multiplying both side by 1 hour (1 h):

$1 kW \cdot h = \frac{1000 J}{1 s} 1 h$

and $1 h = 3600 s$ , so

$1 kWh = \frac{1000 J}{1 s}\cdot 3600 s =3.6\cdot 10^6 J$

So we find the conversion between kWh and Joules. So now we can convert the energy from Joules (2) into kWh:

$1 kWh = 3.6\cdot 10^6 J = x : 423 J\\x=\frac{1 kWh \cdot 423 J}{3.6\cdot 10^6 J}=1.18\cdot 10^{-4}kWh$

And since the cost is $0.0660 per kilowatt-hour, the total cost will be

$C=$0.0660\cdot 1.18\cdot 10^{-4} kWh=7.79\cdot 10^{-6}$ dollars

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4 years ago

How do you know the speed of an electromagnetic wave in a vacuum?

ycow [4]

Electromagnetic waves need no matter to travel - they can travel through empty space (a vacuum). In a vacuum, all electromagnetic waves travel at approximately 3 x 108 m/s - which is the fastest speed possible. ...
Light traveling value through an optical Fibre is, 2 x 108 m/s. Hope that helps.

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3 years ago

A bird can fly at 32 km/h. How long does it take to fly 22 km?​

A bird can fly at 32 km/h. How long does it take to fly 22 km?