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Virty [35]
3 years ago
10

A bird can fly at 32 km/h. How long does it take to fly 22 km?​

Physics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

It takes the bird 0.6875 hour to fly 22 km

Explanation:

Lets revise the relation between the distance, speed and time

→ Distance = speed × time

→ Speed = distance ÷ time

→ Time = distance ÷ speed

A bird can fly at 32 km/h

The speed of the bird is 32 km/h

The bird will fly 22 km

We need to find the time it takes the bird to fly this distance

The speed = 32 km/h

The distance 22 km

Lets use the rule:

→ Time = distance ÷ speed

→ Time = 22 ÷ 32 = 0.6875 hour

<em>It takes the bird 0.6875 hour to fly 22 km </em>

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The greenhouse effect keeps earth warmer than it would normally be. True False
MariettaO [177]

Answer:

The World Is Pure Enough as it is that we don't melt or (lose air) \_/

Explanation:

All people don't have to be concerned about is a disruption of the plethora of gases we already have in our atmosphere and trees need C02 in order to breath and that's what cows produce that's what we breath out and what coal plants and fossil fuels produce the more C02 the more trees produce oxygen because trees breathe in C02 and pop out Oxygen and plus power plants don't produce C02 they produce water vapor so (ALL IN ALL C02 Will not cause the Ice Caps to melt because trees already have that issue covered that's why the scientists said they fixed the global warming issue to keep people from whining about a non-existent problem. so basically its true The greenhouse effect does keep the earth warm halfly because of the hot gases that get trapped in the atmosphere like C02.True

6 0
3 years ago
An initially uncharged 3.47-μF capacitor and a 6.43-kΩ resistor are connected in series to a 1.50-V battery that has negligible
harkovskaia [24]

Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms

Explanation:  In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:

I(t)=io*Exp(-t/τ)

and also we consider that io=V/R=(1.5/6.43*10^3)

=233.28 A

then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6

=22.31 ms

Finally the time to reduce the current to 2.57% of its initial value is obtained from:

I(t)=io*Exp(-t/τ)  for I(t)/io=0.0257=Exp(-t/τ) then

ln(0.0257)*τ =-t

t=-ln(0.0257)*τ=81.68 ms

3 0
3 years ago
A swimming pool is 50 ft wide and 100 ft long and its bottom is an inclined plane, the shallow end having a depth of 4 ft and th
Nina [5.8K]

Explanation:

We define force as the product of mass and acceleration.

F = ma

It means that the object has zero net force when it is in rest state or it when it has no acceleration. However in the case of liquids. just like the above mentioned case, the water is at rest but it is still exerting a pressure on the walls of the swimming pool. That pressure exerted by the liquids in their rest state is known as hydro static force.

Given Data:

Width of the pool = w = 50 ft

length of the pool = l= 100 ft

Depth of the shallow end = h(s) = 4 ft

Depth of the deep end = h(d) = 10 ft.

weight density = ρg = 62.5 lb/ft

Solution:

a) Force on a shallow end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(4)}{2}(2(0)+4)

F = 25000 lb

b) Force on deep end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(10)}{2} (2(0)+10)

F = 187500 lb

c) Force on one of the sides:

As it is mentioned in the question that the bottom of the swimming pool is an inclined plane so sum of the forces on the rectangular part and triangular part will give us the force on one of the sides of the pool.

1) Force on the Rectangular part:

F = \frac{pg(l.h)}{2}(2(x_{1} )+ h)

x_{1} = 0\\h_{s} = 4ft

F = \frac{(62.5)(100)(2)}{2}(2(0)+4)

F =25000lb

2) Force on the triangular part:

F = \frac{pg(l.h)}{6} (3x_{1} +2h)

here

h = h(d) - h(s)

h = 10-4

h = 6ft

x_{1} = 4ft\\

F = \frac{62.5 (100)(6)}{6} (3(4)+2(6))

F = 150000 lb

now add both of these forces,

F = 25000lb + 150000lb

F = 175000lb

d) Force on the bottom:

F = \frac{pgw\sqrt{l^{2} + ((h_{d}) - h(s)) } (h_{d}+h_{s})   }{2}

F = \frac{62.5(50)\sqrt{100^{2}(10-4) } (10+4) }{2}

F = 2187937.5 lb

7 0
3 years ago
An 1647 w toaster, a 1592 w electric frying pan, and a 81 w lamp are plugged into the same outlet in a 120-v circuit. (the three
yanalaym [24]

Since all of the appliances ... and everything else in the house that's
plugged into a wall outlet ... are all in parallel, they don't have any
effect on each other.  They don't know about each other.  The
question asks about the frying pan, so the toaster and the lamp
have no effect  on the answer.

The frying pan has 120 V applied to it, and it produces 1592 watts
of heat.

Power = (voltage)·(current)

1592 watts = (120 v)·(current)

Divide each side by 120v:

Current = (1592 watts) / (120 volts)

Current = 13.27 Amperes
6 0
3 years ago
The higher an electromagnetic wave's frequency, the lower its
Pepsi [2]

Answer:

The higher an electromagnetic wave's frequency, the lower its wavelength

~batmans wife dun dun dun...

7 0
3 years ago
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