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Natalija [7]
4 years ago
12

Density of Unknown Substance

Chemistry
1 answer:
8090 [49]4 years ago
3 0
I need points sorry
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Zn(s) + 2HCl(aq) -> ZnCl2(aq) + H2(g) Which half reaction correctly describes the oxidation that is taking place?
abruzzese [7]
Zn (s) -> Zn+2 (aq) + 2e-

Zn (s) with a neutral charge is oxidized and looses two electrons in the process to form ZnCl2 (aq) where Zn has a charge of 2+.
8 0
3 years ago
Read 2 more answers
Convert the following temperature to c 67k b) 1671k
kap26 [50]
  • Convert Kelvin to °c

(a) 67°c

Formula:-

k=°c+273

°c = 273 - k

°c = 273-67= 206 °c

(b) 1671 k

k=°c+273

°c = 273 - k

°c= 273-1671 = -1398°c

8 0
3 years ago
1a) consider the mixed aldol condensation reaction of 1-methylcyclopentane-1-carbaldehyde (shown below) and 3,3-dimethyl-2-butan
zubka84 [21]
Aldehydes and ketones having α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH). 

The initial product formed during this reaction is β-hydroxy alcohol, which then undergoes dehydration to form α,β-unsaturated aldehyde or ketone.

In present case, 3,3-dimethyl-2-butanone  has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
 5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. 

The complete reaction product formed is shown below. 

7 0
4 years ago
Read 2 more answers
A given atom has 3 protons, 4 neutrons, and 3 electrons. Describe how you can use those three values to describe the structure,
ELEN [110]
Charge # = protons - electons 

Mass # = protons + neutrons 

so that would be 

3-3= charge#
3+4= mass#
3 0
3 years ago
A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
Mkey [24]

The initial volume is 116.65 mL

<u>Explanation:</u>

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Given:

Temperature, T₁ = 22°C

T₂ = 86°C

Volume, V₂ = 456 m

V₁ = ?

According to Charle's law:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

Substituting the values:

\frac{V_1}{22} =\frac{456}{86} \\\\V_1 = \frac{456 X 22}{86} \\\\V_1 = 116.65 mL

Therefore, the initial volume is 116.65 mL

3 0
3 years ago
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