The pH at the equivalence point always not equal to 7 in a neutralization titration when titration occur between weak acid and weak base , strong acid and weak base or strong base weak acid. The reason behind it is given as,
- At equivalence point the product is present by reacting from acid and base.
- So, when weak acid titrate with strong base then the solution will be weak base at equivalence point.
When strong acid is neutralize with strong base then it form neutral product at the equivalence point. Hence the final conclusion is that the pH of the solution in which titration is takes place between strong acid and strong base is 7 that is neutral left titration between all type of acids and bases ha pH not equal to 7 .
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The symbol for carbon is simply C
Answer:
0.653
Explanation:
1)
M1V1 = M2V2
M1 = 5.04 M
V1 = 229 mL ( you take only this volume)
V2 = 921 mL
5.04*229 = M2 * 921
M2 = (5.04*229)/921 Molarity
2)
M1V1 = M2V2
M1 = (5.04*229)/921
V1 = 100 mL
V2= 192 mL
(5.04*229)/921 *100 = M2 * 192
M2 = [(5.04*229)/921 *100]/192 = 0.653 final molarity
Answer:
H2O is the base dissociating for H3O+.
Answer:
Option B
Explanation:
The name of the molecule is;
1,1,1,3,3,3-Hexachloropropanone
Now, we can see that it contains propanone which is also called acetone. So it will have a double bond with Carbon(C) and Oxygen (O).
Option B has that double bond between C and O that indicates it propanone or acetone.
Thus, it is the correct option.
