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scZoUnD [109]
3 years ago
6

What gives the color and shape characteristics to flames in a fire?

Chemistry
1 answer:
zalisa [80]3 years ago
8 0

Answer:

Different ions of different elements (usually metals) make a flame burn with a characteristic color when introduced into the reaction zone; the different colors are caused by the different quantized energy levels of the electrons in the different atoms.

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IMPORTANT IMPORTANT NEED TO GET OFF SOON BC ITS MY BROTHERS BIRTHDAY PLEASEEEE NEED THIS EXTREMELY BAD ❤️ FOR A BIG GRADE TOO
frosja888 [35]

its d because it has to be diagnoly to the right

8 0
3 years ago
Read 2 more answers
CaC2 + 2H2O(I) = C2H2(g) + Ca(OH)2(aq) how many grams of Ca(OH)2 would be formed with 3.20 moles of CaC2?
Jobisdone [24]

Answer:

236.8 g

Explanation:

From the reaction equation;

CaC2 + 2H2O(I) --------> C2H2(g) + Ca(OH)2(aq)

Since;

1 mole of CaC2 yields 1 mole of Ca(OH)2

It follows that 3.20 moles of CaC2 also yields 3.2 moles of Ca(OH)2

Mass of Ca(OH)2 = number of moles * molar mass

molar mass of Ca(OH)2 = 74 g/mol

Mass of Ca(OH)2 = 3.20 moles * 74 g/mol =

Mass of Ca(OH)2 = 236.8 g

3 0
3 years ago
In every balanced chemical equation,each side of the equation has the same number of?
kipiarov [429]

In every balanced chemical equation, each side of the equation has the same number of <u>atoms</u> of reactants and products.

For example, let's take this chemical equation.

This is the chemical equation for carbon monoxide reacting with dihydrogen to form octane and water.

8 CO + 17 H2 → C8H18 + 8 H2O

On this side, we have 8 carbon monoxide atoms and 34 dihydrogen atoms.

On the other side, we have 8 carbon atoms and 18 hydrogen atoms + 16 hydrogen atoms.

Therefore, even though the coefficients are different there is still an equal number of atoms on each side.

8 Carbon Monoxide , 34 Dihydrogen = 8 Carbon Monoxide + 34 Dihydrogen

4 0
3 years ago
Imagine a made-up pol
zheka24 [161]

Answer:

No change to the cation  Add -ide to the anion

Question 1 and .2

Explanation:

6 0
3 years ago
10. What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its
Sergeu [11.5K]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 20°C - 25°C

ΔT  = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C =  c

c = 4016.64 j/g.°C

4 0
3 years ago
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