Answer:
Q = 60192 j
Explanation:
Given data:
Volume of water = 0.45 L
Initial temperature = 23°C
Final temperature = 55°C
Amount of heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 55°C - 23°C
ΔT = 32°C
one L = 1000 g
0.45 × 1000 = 450 g
Specific heat capacity of water is 4.18 j/g°C
Q = m.c. ΔT
Q = 450 g. 4.18 j/g°C. 32°C
Q = 60192 j
Answer:
Ammonium bromide can be prepared by the direct action of hydrogen bromide on ammonia. It can also be prepared by the reaction of ammonia with iron(II) bromide or iron(III) bromide, which may be obtained by passing aqueous bromine solution over iron filings.
Explanation:
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Answer:
280 g
Explanation:
Let's consider the decomposition of ammonium nitrate.
NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)
We can establish the following relations:
- The molar mass of NH₄NO₃ is 80.04 g/mol.
- The molar ratio of NH₄NO₃ to N₂ is 1:1.
- The molar mass of N₂ is 28.01 g/mol.
The mass of N₂ produced when 800 g of NH₄NO₃ react is:
1. Earth can sustain life the moon cannot
2.Earth has oxygen moon does not.
3. Moon is not known to have life
Elements:
• atom
• cannot
• Periodic Table
Compounds:
• atoms
• chemically
• cannot
Mixtures:
• elements or compounds
• homogeneous
• heterogeneous
