Answer:
E = 1.2443*10⁶ N/C
Explanation:
R = 41.6 cm = 0.416 m
Q₁ = 8.55 μC = 8.55*10⁻⁶C
Q₀ = 4.43 μC = 4.43*10⁻⁶C
r = 17.9 cm = 0.179 m
K = 9*10⁹ N*m²/C²
Since r < R we can apply Gauss's Law as follows
E = K*Q₀ / r²
⇒ E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²
⇒ E = 1.2443*10⁶ N/C
1. HCl (H:1, Cl 35.5) ---> 1+35.5 = 36.5
2. FeS (Fe:56, S:32) ---> 56+32 = 88
3. Cl2 (Cl:35.5) ---> 35.5 x 2 = 71
4. CaC03 (Ca:40, C: 12, O: 16) ---> 40 + 12 + 3(16) = 100
5. Fe0 (Fe: 56, O: 16) ---> 56+16=72
Answer:
Option C. Energy Profile D
Explanation:
Data obtained from the question include:
Enthalpy change ΔH = 89.4 KJ/mol.
Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)
ΔH = Hp – Hr
Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.
If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.
Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.
Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.
Answer:
Ans: 2
Explanation:
The concentration of reactants and the concentration of products are constant.
Answer:
this one is hard
Explanation:
but it's iron because the sodium so yea there u go.
