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Sloan [31]
4 years ago
8

The reactants of two chemical reactions are shown.

Chemistry
2 answers:
Ludmilka [50]4 years ago
6 0

Answer:

C)

Explanation:

The first step is to write the <u>whole reactions</u>:

A)HCl~+~NaOH~->~H_2O~+~NaCl

B)Cu~+~AgNO_3~->~Cu(NO_3)_2~+~Ag

In A) reaction we will have an <u>acid-base reaction</u> (double replacement reaction). In this reaction, the <u>oxidation number</u> is the same for all atoms on both sides of the reaction.

In B) the <u>oxidation number</u> of Cu will change from zero to +2 and the <u>oxidation number</u> of Ag will change from +1 to zero. So, the Cu will be <u>oxidized </u>and the Ag will <u>reduce</u>. So, if we have a redox reaction for B) the charge must be equal on both sides.

kozerog [31]4 years ago
3 0

Answer:

it is A

Explanation:

because the forward reation will give salt and water why the backward reaction will give base and acid

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leonid [27]

Answer:

Solution A is correct.

Explanation:

Strong acids or bases are assumed to dissociate completely when in a aqueous solution.

3 0
3 years ago
A student is asked to identify an element that contains 2 valence electrons and is inert (stable). At which location in this per
krek1111 [17]

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i think the answer is helium (top right in periodic table)

6 0
3 years ago
A Potassium isotope contains 19 protons, 19 electrons and 21 neutrons. What is its mass number? 40​
OlgaM077 [116]

Answer:

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Explanation:

you add 19+19 the subtract 21. I think

7 0
4 years ago
What is the density of an object if it has a mass of 73 grams and a volume of 3.8cm3?
SashulF [63]

The density of the object is 19 g/cm³.

The mass of the object is 73 g.

The volume of the object is 3.8 cm³.

Density = mass/volume = 73 g/3.8 cm³ = 19 g/cm³

8 0
3 years ago
A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many
ladessa [460]
The amount of HCl required for one experiment - 13.5 µl 
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L 
since one experiment uses up - 13.5 x 10⁻⁶ L 
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L  = 1.8 x 10⁴ times 
the experiment can be carried out 18000 times 
6 0
3 years ago
Read 2 more answers
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