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Sloan [31]
3 years ago
8

The reactants of two chemical reactions are shown.

Chemistry
2 answers:
Ludmilka [50]3 years ago
6 0

Answer:

C)

Explanation:

The first step is to write the <u>whole reactions</u>:

A)HCl~+~NaOH~->~H_2O~+~NaCl

B)Cu~+~AgNO_3~->~Cu(NO_3)_2~+~Ag

In A) reaction we will have an <u>acid-base reaction</u> (double replacement reaction). In this reaction, the <u>oxidation number</u> is the same for all atoms on both sides of the reaction.

In B) the <u>oxidation number</u> of Cu will change from zero to +2 and the <u>oxidation number</u> of Ag will change from +1 to zero. So, the Cu will be <u>oxidized </u>and the Ag will <u>reduce</u>. So, if we have a redox reaction for B) the charge must be equal on both sides.

kozerog [31]3 years ago
3 0

Answer:

it is A

Explanation:

because the forward reation will give salt and water why the backward reaction will give base and acid

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Considering 2N2H4(g) + N2O4(g) -&gt; 3N2(g) +4H2O(g)
Tema [17]

Answer:

107.8

Explanation:

64 gram of N2H4 produce 72 gram of H20

then by crossmultiplication

64*121.3/72=107.82

3 0
2 years ago
A student performs an experiment to find the percentage of water in a hydrate. He determines that the hydrate contains 22% water
Stels [109]

Answer:

A feasible error could have been the removal of the sample before all water evaporated.

Explanation:

In order to determine the percentage of water in an hydrate, an experiment that could be performed is the heating of the sample until the mass does not change. If the student heated the sample an insufficient amount of time, water will be present in the sample, thus reducing the percentage reported.

4 0
3 years ago
What general rule can be followed when choosing a type of solvent for a particular solute
ehidna [41]
General 'rule' - "like dissolves like". The solubility of a solute in a solvent (that is, the extent of the mixing of the solute and solvent species) depends on a balance between the natural tendency for the solute and solvent species to mix and the tendency for a system to have the lowest energy possible.

Hope this helps :p
4 0
3 years ago
Can anyone answer these ? 40 points !!
lesantik [10]

1st one is D

2nd one is A

4 0
3 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
max2010maxim [7]

Answer:

The answer to your question is: Initial temperature of copper = 67.1°C

Explanation:

Data

mass Copper = 248 g

volume Water = 390 ml

T1 water = 22.6°C

T2           = 39.9°C

T1 copper = ?

Specific heat water = 1 cal/g°C

Specific heat copper = 0.092 cal/g°C

Formula       copper             water

Heat is negative for copper because it releases heat

                  - mCp(T2 - T1) = mCp(T2 - T1)                  

                  - (248)(39.9 - T1) = 390 (1)((39.9 - 22.6)           Substitution

                 -9895.2 + 248T1 = 390(17.3)                             Simplification

                 -9895.2 + 248T1 = 6747

                 248 T1 = 6747 + 9895.2

                 248 T1 = 16642.2

                 T1 = 16642.2 / 248

                 T1 = 67.1 °C                                                         Result

6 0
3 years ago
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