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3 years ago

The reactants of two chemical reactions are shown.

Chemistry

2 answers:

Ludmilka [50]3 years ago

6 0

Answer:

Explanation:

The first step is to write the whole reactions:

A) $HCl~+~NaOH~->~H_2O~+~NaCl$

B) $Cu~+~AgNO_3~->~Cu(NO_3)_2~+~Ag$

In A) reaction we will have an acid-base reaction (double replacement reaction). In this reaction, the oxidation number is the same for all atoms on both sides of the reaction.

In B) the oxidation number of Cu will change from zero to +2 and the oxidation number of Ag will change from +1 to zero. So, the Cu will be oxidized and the Ag will reduce. So, if we have a redox reaction for B) the charge must be equal on both sides.

kozerog [31]3 years ago

3 0

Answer:

it is A

Explanation:

because the forward reation will give salt and water why the backward reaction will give base and acid

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Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2

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Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

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Answer:

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Explanation:

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The detailed reaction mechanism is attached to this answer.

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