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gizmo_the_mogwai [7]
3 years ago
8

I need the equation C14H3O+o2 balanced

Chemistry
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

C14H3O + O2 = CO2 + H2O.

Explanation:

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Determine the [OH-], pH, and pOH of a solution with a [H+] of 0.090 M at 25 °C. [OH-] = pH = pOH = 0 POH =
ValentinkaMS [17]

Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95

The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

5 0
2 years ago
Read 2 more answers
True or False.
mrs_skeptik [129]
True because it s all true
4 0
3 years ago
Read 2 more answers
How does the numbers valence electrons in oxygen compare to the valence electrons in hydrogen?
elena-s [515]

Answer:

Determine the total number of valence electrons in the molecule or ion.

Each H atom (group 1) has 1 valence electron, and the O atom (group 16) has 6 valence electrons, for a total of 8 valence electrons

Explanation:

8 0
2 years ago
Which of the following would lose heat the fastest?
Molodets [167]

Answer:

15 grams of water

Explanation:

15 grams of water of water would lose heat the faster compared to higher masses of water.

Water generally is a poor conductor heat.

  • To heat up a unit of water, significant amount of energy must be added to the body of water.
  • With time, the body continues to increase in temperature.
  • A 500g mass of water will take more time to lose heat.
5 0
3 years ago
Carbon-14 has a half-life of approximately 5700 years. How much of a 1000g sample will be left undecayed and still radioactive a
Artist 52 [7]

Answer:

option C is correct (250 g)

Explanation:

Given data:

Half life of carbon-14 = 5700 years

Total amount of sample = 1000 g

Sample left after 11,400 years = ?

Solution:

First of all we will calculate the number of half lives passes during 11,400 years.

Number of half lives = time elapsed/ half life

Number of half lives = 11,400 years/5700 years

Number of half lives = 2

Now we will calculate the amount left.

At time zero = 1000 g

At first half life = 1000 g/2 = 500 g

At second half life = 500 g/2 = 250 g

Thus, option C is correct.

4 0
3 years ago
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