Answer:
-514 kJ/mol
Explanation:
The bond enthalpy which is also known as bond energy can be defined as the amount of energy needed to split one mole of the stated bond. The change in enthalpy of a given reaction can be estimated by subtracting the sum of the bond energies of the reactants from the sum of the bond energies of the products.
For the given chemical reaction, the change in enthalpy of the reaction is:
Δ
[2(409) + 4(388) + 3(496) - 4(630) - 4(463)] kJ/mol = 818 + 1552 + 1488 - 2520 - 1852 = -514 kJ/mol
The balance chemical equation is :
2HCL + Na2CO3 -----> 2NaCl + H2O + CO2
According to Question,
Given,
Molarity of HCL = 1.75 m
Sodium Carbonate (Na2CO3) = 0.100 m
For finding out the molarity,
c = n solute / Vsolution => n = c.Vsolution
nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3
0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3
= 0.150 moles of H3O^+
As we have already know the molarity of HCL , we easily calculate what volumes by many moles.
c = nsolute / Vsolution => Vsolution = nsolute / c
VH3O^+ = 0.150 moles / 1.75 mol L^-1 = 0.0857 L
To know more about Molarity here :
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B. A pure substance made up of one type of atom
Answer: The ∆Hf is -384.7kj/mol
Explanation:
H2O +SO3-----H2SO4
-285.8 +(-98.9------- -384.7kj/mol
answer of this question is [Ar]3d8 4s2
