When:
Fe(OH)3 ↔
Fe3+ + 3OH-so, each 1 mol Fe3+ → 3 mol OH-
and when [OH]
= 1.2 x 10^-5∴ [Fe3+] = (1.2 x 10^-5) / 3
= 4 x 10^-6when
Keq = [Fe3+][OH]^3 = (4 x 10^-6) (1.2 x 10^-5)^3
∴Keq = 6.9 x 10^-21
Answer:
3.6mol Li
Explanation:
To get the amount of moles from the mass we divide the mass by the molar mass.
25g ÷ 6.941g/mol = 3.6mol Li
If we draw the lewis structure, we can see that all Cl
atoms are all connected to the B atom. Now Cl atoms has 7 electrons each on its
outermost shell while B can donate 3 electrons. So by octet rule, each Cl will
gain 1 electron each from the B atom. From the Lewis structure, we can see that
there are actually No Lone pairs on the central atom.
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Answer:
0.51M
Explanation:
Given parameters:
Initial volume of NaBr = 340mL
Initial molarity = 1.5M
Final volume = 1000mL
Unknown:
Final molarity = ?
Solution;
This is a dilution problem whereas the concentration of a compound changes from one to another.
In this kind of problem, we must establish that the number of moles still remains the same.
number of moles initially before diluting = number of moles after dilution
Number of moles = Molarity x volume
Let us find the number of moles;
Number of moles = initial volume x initial molarity
Convert mL to dm³;
1000mL = 1dm³
340mL gives = 0.34dm³
Number of moles = initial volume x initial molarity = 0.34 x 1.5 = 0.51moles
Now to find the new molarity/concentration;
Final molarity = = = 0.51M
We can see a massive drop in molarity this is due to dilution of the initial concentration.