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Oksana_A [137]
2 years ago
11

Use the following information S(s)+O2(g)→SO2(g)S(s)+O2(g)→SO2(g), ΔH∘ΔH∘ = -296.8kJkJ SO2(g)+12O2(g)→SO3(g)SO2(g)+12O2(g)→SO3(g)

, ΔH∘ΔH∘ = -98.9kJkJ to calculate ΔH∘fΔHf∘ for H2SO4(aq)H2SO4(aq) (in kilojoules per mole). [For H2O(l),ΔH∘fH2O(l),ΔHf∘ = -285.8kJ/molkJ/mol]. Express your answer using four significant figures
Chemistry
1 answer:
Sedaia [141]2 years ago
4 0

Answer: The ∆Hf is -384.7kj/mol

Explanation:

H2O +SO3-----H2SO4

-285.8 +(-98.9------- -384.7kj/mol

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0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K. When equilibrium is reache
HACTEHA [7]

Answer:

12.531 grams will be the final mass of calcium carbonate.

Explanation:

CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)

Partial pressure of carbon dioxide gas at equilibrium =P=0.220 atm

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

PV=nRT( ideal gas equation)

n=\frac{PV}{RT}=\frac{0.220 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.06960 mol

According to reaction , 1 mole of carbon dioxide gas is formed from 1 mole of calcium carbonate,0.06960 mole of carbon dioxide gas will be obtained from :

\frac{1}{1}\times 0.06960 mol=0.06960 mol calcium carbonate

Moles of calcium carbonate at equilibrium = 0.100 mol - 0.06960 mol = 0.03040 mol

After addition of 0.300 atm of carbon dioxide gas, more amount of calcium carbonate will be be formed.

Here, at the same temperature, the equilibrium pressure of the carbon dioxide gas is 0.220 atm so, entire 0.300 atm of carbon dioxide will get convert to calcium carbonate.

So amount moles of carbon dioxide gas added = moles of calcium carbonate formed after re-establishment of an equilibrium :

Partial pressure of carbon dioxide gas added at equilibrium =P=0.300 atm

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

PV=nRT( ideal gas equation)

n=\frac{PV}{RT}=\frac{0.300 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.09491 mol

Moles of calcium carbonate = 0.09491 mol

Total moles of calcium carbonate in the container :

=0.03040 mol + 0.09491 mol = 0.12531 mol

Mass of 0.12531 moles of calcium carbonate :

0.12531 mol × 100 g/mol = 12.531 g

12.531 grams will be the final mass of calcium carbonate.

4 0
3 years ago
How does the state of atoms in a neon light change when light is emitted?
Blababa [14]
The state of atoms in a neon light when light is emitted is loss of energy.
5 0
2 years ago
Read 2 more answers
Is anyone good at chemistry if so can someone help me please ?<br><br> (NO LINKS)
Mkey [24]

This requires familiarity with the different theories (or concepts) of acids and bases.

On the Arrhenius concept, an acid is a substance that produces an H⁺ ion in water such that the H⁺ concentration increases, and a base is a substance that produces an OH⁻ ion in water such that the OH⁻ concentration increases.

On the Brønsted–Lowry concept, an acid is a substance that donates a proton (which is basically an H⁺ ion) in a solvent, and a base is a substance that accepts a proton in a solvent.

On the Lewis concept, an acid is a substance that accepts an electron pair in a solvent, and a base is a substance that donates an electron pair in a solvent.

The concepts become progressively broader, i.e., the Arrhenius concept is the most restrictive and the Lewis concept is the least restrictive. As a corollary, an Arrhenius acid or base is also both a Brønsted–Lowry acid or base and a Lewis acid or base, respectively; a Brønsted–Lowry acid or base is not necessarily an Arrhenius acid or base, but an Arrhenius acid or base is also a Lewis acid or base, respectively. And finally, a Lewis acid or base may not necessarily be either an Arrhenius or a Brønsted–Lowry acid or base.

So, with the above concepts in mind, we can match the statements in column A with the type of acid or base in column B:

\begin{center}\begin{tabular}{ c c } 1 & Bronsted Lowry acid \\  2 & Bronsted Lowry base \\   3 & Arrhenius acid \\ 4 & Arrhenius base \\ 5 & Lewis base \\ 6 & Lewis acid\end{tabular}\end{center}

6 0
3 years ago
What is the identity of the atom shown?
jonny [76]
Niterogen if I’m wrong please correct me
3 0
2 years ago
Read 2 more answers
(a) ions in a certain volume of .20M NaCl (aq) are represented in the box above on the left. in the box above on the right, draw
mamaluj [8]

Answer:

  • The first picture attached is the diagram that accompanies the question.

  • The<u> second picture attached</u> is the diagram with the answer.

Explanation:

In the box on the left there are 8  Cl⁻ ions and 8 Na⁺ ions.

The dissociaton equation for NaCl(aq) is:

  • NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)

The dissociation equation for CaCl₂ (aq)  is:

  • CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.

Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half)  and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).

Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.

4 0
3 years ago
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