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kap26 [50]
3 years ago
10

List an example of earth landforms changing due to weathering and erosion

Chemistry
1 answer:
Helga [31]3 years ago
4 0

Answer:

i believe the grand canyon is an example

Explanation:

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Water evaporating from a puddle is an example of a
Flauer [41]
It is an example of physical change. The molecules are not changing, so it is not chemical, and a physical property is something that a physical thing has.


5 0
3 years ago
Read 2 more answers
The tarnish that forms on objects made of silver is solid silver sulphide. This can be removed by reacting it with aluminium met
steposvetlana [31]

Answer:

5.83 mol.

Explanation:

  • From the balanced reaction:

<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>

It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.

Al reacts with Ag₂S with (2: 3) molar ratio.

<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>

<em />

  • The limiting reactant is Ag₂S.
  • The excess "left over" reactant is Al.

The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

6 0
3 years ago
PLEASE HELP IT DUE TODAY WILL GIVE 100 BRAINLY POINTS AND BRAINLYEST
inessss [21]

Answer:

1. The energy intensity from the ruler going through the air

2. This one is pretty simple, you can add or take away things. This question is just asking you to list sounds from high pitch, to lowest pitch. Here are mine:

Timer

Microwave

Mouse clicking

Dog Barking

Voice

Typing

Knocking on door

Breathing

Foot Steps

Explanation:

4 0
2 years ago
A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.
joja [24]
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1)  × 100% =  0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

5 0
3 years ago
How many moles are in 213 grams of NaCl?
Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0
3 years ago
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