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sattari [20]
3 years ago
13

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ = 0

.001 millimeters. A random sample of 15 rings has a mean diameter of x = 74.036 millimeters.
(a) Construct a 99% two-sided confidence interval on the mean piston ring diameter.
(b) Construct a 99% lower-confidence bound on the mean piston ring diameter. Compare the lower bound of this confidence interval with the one in part (a).
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

The answer along with the explanation is provided in the attached document.

Explanation:

The explanation is given in attached document file.

Download docx
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In the rectangle below, E1=2x -2, FH=3x+6, and m 4IHG =35°.Find Gl and m LIEH
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Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

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Substituting the given expression for each segment in the first equation, we get:

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\begin{gathered} 3x+6=4x-4, \\ 3x+6+4=4x, \\ 3x+10=4x, \\ 4x-3x=10, \\ x=10. \end{gathered}

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EI=2*10-2=20-2=18.

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Now, to determine the measure of angle IEH, we notice that:

\Delta HFG\cong\Delta GEH,

therefore,

\measuredangle GHF\cong\measuredangle HGE.

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

m\measuredangle IEH=90^{\circ}-35^{\circ}=55^{\circ}.

<h2>Answer: </h2>\begin{gathered} m\operatorname{\measuredangle}IEH=55^{\operatorname{\circ}}, \\ GI=18. \\  \end{gathered}

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1 year ago
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