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3 years ago

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An automobile with a radio antenna 1.0 m long generates an emf, V1, since it is traveling at 100.0 km/h in a location where the

Earth's horizontal magnetic field is 5.5x10-5T. At some time, the radio antenna doubles in length and the car begins traveling at a quarter of the original speed. What is the ratio of the new emf generated, V2, to the original emf. V1? 0.5V1 0.125 V1 111 0.75V1

2 answers:

trapecia [35]3 years ago

5 0

Answer:

option A

Explanation:

given,

length of antenna = 1 m

traveling at speed = 100 Km/h

Earth's horizontal magnetic field is 5.5 x 10⁻⁵ T

radio antenna doubles in length (l₂ = 2 l)

car begins traveling at a quarter of the original speed (v₂ = v/4)

ratio of new emf

we know, ε = B l v

V₁ = B₁ l₁ v₁...........(1)

V₂ = B₂ l₂ v₂...........(2)

dividing equation (2) from (1)

$\dfrac{V_2}{V_1}=\dfrac{B_2 l_2 v_2}{B_1 l_1 v_1}$

$\dfrac{V_2}{V_1}=\dfrac{ (2 l)(\dfrac{v}{4})}{ l v}$

$\dfrac{V_2}{V_1}=\dfrac{1}{2}$

V₂ = 0.5 V₁

the correct answer is option A

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