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DiKsa [7]
3 years ago
14

An automobile with a radio antenna 1.0 m long generates an emf, V1, since it is traveling at 100.0 km/h in a location where the

Earth's horizontal magnetic field is 5.5x10-5T. At some time, the radio antenna doubles in length and the car begins traveling at a quarter of the original speed. What is the ratio of the new emf generated, V2, to the original emf. V1? 0.5V1 0.125 V1 111 0.75V1
Physics
2 answers:
trapecia [35]3 years ago
5 0

Answer:

option A

Explanation:

given,

length of antenna = 1 m

traveling at speed = 100 Km/h

Earth's horizontal magnetic field is 5.5 x 10⁻⁵ T

radio antenna doubles in length (l₂ = 2 l)

car begins traveling at a quarter of the original speed (v₂ = v/4)

ratio of new emf

we know, ε = B l v

V₁ = B₁ l₁ v₁...........(1)

V₂ = B₂ l₂ v₂...........(2)

dividing equation (2) from (1)

\dfrac{V_2}{V_1}=\dfrac{B_2 l_2 v_2}{B_1 l_1 v_1}

\dfrac{V_2}{V_1}=\dfrac{ (2 l)(\dfrac{v}{4})}{ l v}

\dfrac{V_2}{V_1}=\dfrac{1}{2}

V₂ = 0.5 V₁

the correct answer is option A

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3 0

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3 years ago
You have just landed on Planet X. You take out a ball of mass 101 g , release it from rest from a height of 16.0 m and measure t
IRINA_888 [86]

Answer:

0.3817 N

Explanation:

Remark

One thing is certain: the ball has a mass of 101 grams wherever it is in the universe. That is not true of the force. The force on the moon is a whole lot less than it is on earth, and maybe planet x as well.

Givens

m = 101 g

vi = 0       That's what at rest means.

t = 2.91 s

d = 16 m

F= ?

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d = vi*t + 1/2*a * t^2

Force = m * a

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16 = 0 + 1/2 a * 2.91^2

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8 0
3 years ago
A car drives past a pole at 40km/hr. Describe the motion from the point of view of a) the car, and b) the pole. Thanks in advanc
ki77a [65]
I was going to beg off until tomorrow, but this one is nothing like those others.
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To put a finer point on it, let's give the car a direction.  Say it's driving North.

a).  From the point of view of the car, its driver, and passengers if any,
the pole moves past them, heading south, at 40 km/hour .

b).  From the point of view of the pole, and any bugs or birds that may be
sitting on it at the moment, the car and its contents whiz past them, heading
north, at 40 km/hour.

c).  A train, steaming North at 80 km/hour on a track that exactly parallels
the road, overtakes and passes the car at just about the same time as
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The rail motorman, fireman, and conductor all agree on what they have
seen. From their point of view, they see the car moving south at 40 km/hr,
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The car and the pole are both seen to be moving south.  BUT ... Since the
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That's what everybody on the train sees.

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Finally ... since you posed this question as having something to do with your
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Now I ask you ... was that sloppy or what ? ! ? 

Of course, I came along later and did the same thing with the train, but I am
not here to make fun of myself !  Only of others.

The point is . . . the whole purpose of this question, obviously, is to get the student accustomed to the concept that speed has no meaning in and of itself, only relative to something else.  And if the given speed of the car ...40 km/hour ... was measured relative to anything else but the ground on which it drove, as we assumed it was, then all of the answers in (a) and (b) could have been different.

And now I believe that I have adequately milked this one for 50 points worth.


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