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aleksklad [387]

3 years ago

15

During science class, Ava and Justin were discussing the rotation of the Sun and debating over which model would best illustrate

how the Suns rotates. Which of the models shown below would best represent the rotation of the Sun? с B D

1 answer:

agasfer [191]3 years ago

3 0

Answer:

it would b B

Explanation:

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A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.

Masja [62]

Answer:

0.368 cm

Explanation:

x = distance by which the mercury rise

d = depth of the water = 10 cm = 0.10 m

ρ = density of water = 1000 kgm⁻³

ρ' = density of mercury = 13600 kgm⁻³

P₀ = atmospheric pressure

Using equilibrium of pressure on both side

P₀ + ρ g d = P₀ + ρ' g (2x)

(1000) (0.10) = (13600) (2x)

x = 0.00368 m

x = 0.368 cm

8 0

3 years ago

An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.

Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{water}$

$F_{b}=79.1-21.8$

$F_{b}=57.3\ N$

$F_{b}=\rho g h$

Put the value into the formula

$57.3=1000\times V\times 9.8$

$V=\dfrac{57.3}{1000\times9.8}$

$V=5.84\times10^{-3}\ m^3$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho Vg$

$79.1=\rho\times5.84\times10^{-3}\times9.8$

$\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}$

$\rho=1382\ kg/m^3$

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{oil}$

$F_{b}=79.1-48.4$

$F_{b}=30.7\ N$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho_{oil} Vg$

$30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8$

$\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}$

$\rho=536.4\ kg/m^3$

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0

3 years ago

If gravity did not affect the path of a horizontally thrown ball the ball would ____

Setler79 [48]

If gravity did not affect the path of a horizontally thrown ball the ball would eventually slow due to air resistance. If the ball were somehow thrown in a vacuum devoid of gravity and air, it would technically continue in a straight line forever.

5 0

3 years ago

If Object C and Object D both have the same momentum, which statement is true? Question 11 options: They both have the same velo

Leya [2.2K]

Answer:

The product of mass times velocity for both objects is the same.

Explanation:

They both have the same velocity. False

They both have the same mass. False: Because two objects of different masses can have the same momentum. The least massive of the two objects will have the greatest kinetic energy.

The product of mass times velocity for both objects is the same. True: Same momentum means that the large mass must have a small velocity; therefore, their product is equal to the small mass times a large velocity.

Mass and velocity is the same for both. False: Based on what was stated for the second option.

7 0

3 years ago

An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10s.Assuming air

Alexandra [31]

The initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

u is the initial velocity of fall = ? m/sec

h is the distance of fall = 200 m

g is the acceleration of free fall = 9.81 m/sec²

H is the height of the building

t is the time period = 10 second

According to Newton's second equation of motion,

$\rm h= ut+\frac{1}{2} gt^2 \\\\\ h-\frac{1}{2} gt^2 =ut \\\\ 200 - 0.5 \times(9.81) \times 10^2 = 10 u \\\\ u = - 29.05 \ m/sec$

- ve shows the direction is downward.The magnitude of the initial velocity is found as;

u = 29.05 m/sec

The height of the building

$\rm H= ut+\frac{1}{2} gt^2 \\\\\ H = 29.05 \times 10 + 0.5 \times 9.81 \times 10^2 \\\\ H = 781 \ m$

Hence the initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.

To learn more about the velocity, refer to the link: brainly.com/question/862972

SPJ1

4 0

2 years ago