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Vera_Pavlovna [14]
2 years ago
11

A microwave oven uses electromagnetic radiation to heat water molecules in food or drink. This radiation has a frequency of 2.45

x 10⁹ Hz. Calculate its energy
Chemistry
1 answer:
fredd [130]2 years ago
5 0

Answer:

1.62 × 10⁻²⁴ J

Explanation:

Step 1: Given and required data

  • Frequency of this radiation (ν): 2.45 × 10⁹ Hz (2.45 × 10⁹ s⁻¹)
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Step 2: Calculate the energy (E) of this electromagnetic radiation

We will use the Planck-Einstein's relation.

E = h × ν

E = 6.63 × 10⁻³⁴ J.s × 2.45 × 10⁹ s⁻¹ = 1.62 × 10⁻²⁴ J

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Volgvan

Answer:

Yes it is hard. For some of us. I already gave up, but now hes coming back. Id say sometimes its useless to get his attention if he never even pays attention to you anyways. It sucks because its so hard to get then to notice you for once.

Explanation:

4 0
3 years ago
1.5 moles of Al is how many<br> atoms?
aev [14]

Answer:

<h2>9.03 × 10²³ atoms </h2>

Explanation:

The number of atoms of Al can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ atoms</h3>

Hope this helps you

4 0
2 years ago
Which moon phase does a solar eclipse occur in?
VARVARA [1.3K]

Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
Write the balanced chemical equation for the reaction between aqueous sodium carbonate and
ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

7 0
3 years ago
A researcher studying the nutritional value of a new candy places a 4.90 g sample of the candy inside a bomb calorimeter and com
snow_lady [41]

Answer:

449730.879 cal/g

Explanation:

Given data:

Mass of sample = 4.9 g

Change in temperature  = 2.08 °C  (275.23 k)

Heat capacity of calorimeter = 33.50 KJ . K⁻¹

Solution:

C(candy) = Q/m

Q = C (calorimeter) × ΔT

C(candy) = C (calorimeter) × ΔT / m

C(candy) =  33.50 KJ . K⁻¹ × 275.23 K / 4.90 g

C(candy) = 9220.205 KJ / 4.90 g

C(candy) =  1881.674 KJ / g

It is known that,

1 KJ /g = 239.006 cal/g

1881.674 × 239.006 = 449730.879 cal/g

8 0
3 years ago
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