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3 years ago

Conflict is A. B. C. D.

Mathematics

1 answer:

QveST [7]3 years ago

5 0

Conflict in Literature is the opposition of two or more characters or forces.

I hope this helps you!

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Peggy wants to run 5 miles in less than 60 minutes. What inequality shows what her rate should be ?

sleet_krkn [62]

The inequality that her rate should be is
<span>5 > 60</span>

8 0

3 years ago

Read 2 more answers

How do i find the scale factor?

AnnyKZ [126]

Answer:

1:3.7

Step-by-step explanation:

1331/27

Then cube root

3.66666666667

Round

3.7

(i believe)

8 0

3 years ago

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig

Nady [450]

Answer:

$D = 45+19*sin(\frac{\pi}{12}*t)$

Step-by-step explanation:

The amplitude (A) and the mean (M) temperature are given by:

$A=\frac{64-26}{2}\\ A= 19\\M=\frac{64+26}{2}\\ M= 45\\$

The mean temperature, 45 degrees. occurs at midnight (t=0) and the frequency is f=24h. Therefore, the temperature D, in degrees, as a function of t, in hours, is:

$D = M+A*sin(\frac{2\pi}{24}*t)\\D = 45+19*sin(\frac{\pi}{12}*t)$

5 0

3 years ago

Need help. please give me a legit answer.

LekaFEV [45]

Theyre all labeled correctly, what exactly is the question?

5 0

2 years ago

Read 2 more answers

Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago