All categories

1 year ago

Determine the empirical formula of the following compound if a sample contains 5.28 gsn and 3.37 gf.

Chemistry

1 answer:

earnstyle [38]1 year ago

4 0

Answer:

SnF2

Explanation:

you divide by the smallest number which is 3.37

You might be interested in

Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

barxatty [35]

Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2. $Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.The electron affinity of $Mg^{2+}$ is zero.

4. $O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

Explanation:

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

The electronic configuration of Mg: $1s^{2}2s^{2}2p^{6}3s^{2}$

By the removal of two electrons from a magnesium element we get $Mg^{2+}$ ion.

$Mg^{2+}$ has inert gas configuration i.e, $1s^{2}2s^{2}2p^{6}$

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of $Mg^{2+}$ is zero.

The ionization energy of $O^{2-}$ is follows.

$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

3 0

3 years ago

N2 + 3H2 + 2NH3 .

HACTEHA [7]

Answer:

Explanation:

7 0

3 years ago

The general formula for

shutvik [7]

The second one, b synthesis reaction

6 0

3 years ago

Read 2 more answers

7. An element's most stable ion forms an ionic compound with chlorine having the formula XCl2. If the ion of element X has a mas

Serhud [2]

Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,

XCl₂ ⇔ X₂⁺ + 2Cl⁻

X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,

No. of electrons = atomic number - charge

36 = atomic number - 2

Atomic number = 38

Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.

Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,

No. of neutrons = mass number - atomic number

= 89 - 38

= 51 neutrons.

4 0

3 years ago

The molecule shown is a

Pani-rosa [81]

c is the answer a benzene

8 0

3 years ago