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3 years ago

9

A frog has a genetic mutation in its skin cells that causes part of its skin to turn orange. The frog will not pass this genetic

onto its offspring because

1 answer:

yaroslaw [1]3 years ago

8 0

Because it is not dominant? that is what im guessing

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The Bay of Fundy is known for its?

DaniilM [7]

The highest tides and rarest whales on earth

3 0

4 years ago

Four rods that obey Hooke's law are each put under tension. (a) A rod 50.0 cm50.0 cm long with cross-sectional area 1.00 mm21.00

deff fn [24]

Answer:

c < a = b

Explanation:

The tensile stress = Force applied/(Cross sectional area)

(a) The applied force = 200 N

The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²

The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa

(b) The applied force = 200 N

The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²

The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa

(c) The applied force = 100 N

The cross sectional area = 2.00 mm² = 2 × 10⁻⁶ m²

The tensile stress = 100 N/(2 × 10⁻⁶ m²) = 50,000,000 Pa = 50 MPa

Therefore, the tensile stress from smallest to largest are;

(a) 50 MPa, < (b) 200 MPa = (a) 200 MPa

Therefore, we have;

c < a = b.

8 0

3 years ago

in a microscope, what happens to the sharpness of the image (resolution) as you switch from low to high power? Plz help!

Roman55 [17]

The "resolution" lowers. This is caused because most optical microscopes bend light. The more light there is, the more it bends. This causes the edges of the object to be blurred, and possibly even blot out the object.

8 0

3 years ago

A communications satellite transmits a radio wave at a frequency of 5 • 10^9 Hz. What is the signal's wavelength? Assume the wav

ycow [4]

Frequency f =5×10^9Hz
Speed of radio waves=speed of light c =3×10^8m/s

Wavelength λ = c/f
= 3×10^8/5×10^9
= 0.06m

3 0

4 years ago

Two small, identical conducting spheres repel each other with a force of 0.045 N when they are 0.15 m apart. After a conducting

Levart [38]

Answer:

$q_1 = \pm 1.68 \times 10^{-7} C$

$q_2 = \pm 6.68 \times 10^{-7} C$

Explanation:

As we know that the force between two small spheres is given as

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 , q_2$ = charges on two small spheres

r = distance between two spheres = 0.15 m

now the force between them is given as

$0.045 = \frac{(9\times 10^9)(q_1q_2)}{0.15^2}$

$q_1q_2 = 1.125 \times 10^{-13}$

now when two spheres are connected together then the charge on them is equally divided

$q = \frac{q_1+q_2}{2}$

now the force between them is given as

$F = \frac{k(\frac{q_1+q_2}{2})^2}{0.15^2}$

$0.070 = \frac{(9\times 10^9)(\frac{q_1+q_2}{2})^2}{0.15^2}$

$q_1 + q_2 = 8.37\times 10^{-7}$

so here we have

$q_1 = \pm 1.68 \times 10^{-7} C$

$q_2 = \pm 6.68 \times 10^{-7} C$

5 0

3 years ago