<span>Answer:
Let m = mass of cannon
Then
10000 = ma
a = 10000/m
v^2 = u^2 + 2as
v^2 = 0 + 2as
84^2 = 2(2.21)(10000/m)
84^2 m = 4.42(10000)
m = 6.264172336
= 6.26 kg
Part 2
Range = u^2sin(2x38)/g
= 84^2sin(76)/9.8
= 698.6129229
= 698.6 m</span>
That's the "Atomic Mass" of the atom.
Answer:
20n
Explanation:
60n - 40n = efficiency of pulley system
20n = efficiency of pulley system
The formulas are-
a=f/m
f=ma
m=f/a
