2 years ago

Answer them all please!!

Physics

1 answer:

stepladder [879]2 years ago

7 0

Answer:

Digestive = large instestine

respiratory = lungs

circulatory red blood cell

neurons=nerves

Explanation:

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If opposite poles repel each other, why does the north end of a compass point to the north pole?

lina2011 [118]

Ratios are fractions

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3 years ago

What is an independent or manipulated variable?

Paha777 [63]

Is the variable you change, independent, I, something I change.

5 0

3 years ago

2 m3 of an ideal gas are compressed from 100 kPa to 200 kPa. As a result of the process, the internal energy of the gas increase

rosijanka [135]

Answer:

work done is -150 kJ

Explanation:

given data

volume v1 = 2 m³

pressure p1 = 100 kPa

pressure p2 = 200 kPa

internal energy = 10 kJ

heat is transferred = 150 kJ

solution

we know from 1st law of thermodynamic is

Q = du +W ............1

put here value and we get

-140 = 10 + W

W = -150 kJ

as here work done is -ve so we can say work is being done on system

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2 years ago

You have a 3.00-liter container filled with N₂ at 25°C and 4.45 atm pressure connected to a 2.00-liter container filled with Ar

LuckyWell [14K]

Answer : The final pressure in the two containers is, 2.62 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

Thus, the expression for final pressure in the two containers will be:

$PV=P_1V_1+P_2V_2$

$P=\frac{P_1V_1+P_2V_2}{V}$

where,

$P_1$ = pressure of N₂ gas = 4.45 atm

$P_2$ = pressure of Ar gas = 2.75 atm

$V_1$ = volume of N₂ gas = 3.00 L

$V_2$ = volume of Ar gas = 2.00 L

P = final pressure of gas = ?

V = final volume of gas = (4.45 + 2.75) L = 7.2 L

Now put all the given values in the above equation, we get:

$P=\frac{(4.45atm)\times (3.00L)+(2.75atm)\times (2.00L)}{7.2L}$

$P=2.62atm$

Thus, the final pressure in the two containers is, 2.62 atm

8 0

2 years ago

Some students fire a rocket of mass 0.150kg into the air. If at the top of it's flight it has a gravitational potential energy o

mamaluj [8]

PE=mgh
150J=(0.150)*(9.8)*h
h=102m

4 0

3 years ago