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melisa1 [442]
3 years ago
10

The chemical equation below shows the reaction between tin (Sn) and hydrogen fluoride (HF). Sn + 2HF mc017-1.jpg SnF2 + H2 The m

olar mass of HF is 20.01 g/mol. How many moles of Sn are required to react with 40 g of HF?
Chemistry
2 answers:
Sergio [31]3 years ago
7 0
Tin and Hydrofluoric Acid reacts as shown,

<span>                              Sn  +  2 HF    </span>→    SnF₂<span>  +  H</span>₂

According to Equation,

40.02 g (2 Moles) HF Required  =  <span>1 Mole of Sn for complete Reaction

So,
              40 g of HF will require  =  X Moles of Sn

Solving for X,
                                       X  =  (40 g </span>× 1 Mole) ÷ 40.02 g

                                       X  =  0.999 Moles  ≈  1 Mole
Result:
            40 g 
of HF requires 1 Mole of Tin (Sn) for complete Reaction to produce SnF₂ and H₂.
PIT_PIT [208]3 years ago
3 0

Answer:

A. 1

Explanation:

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D. The volume of the solvent used was less than 5 liters.

Explanation:

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<em>(MV) before dilution = (MV) after dilution.</em>

M before dilution = 10.0 M, V before dilution = V of stock = ??? L.

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