I thought I could make you day so here is your Anwser.The mass of a sample containing 4.00 mol of H2 is 8.08 g. The molar mass of hydrogen (H2) is 2.02 g/mol. In other words, there are 2.02 g in 1.00 mol of H2. The question is how many grams are in 4.00 mol of H2. Let's use proportion: 2.02 g : 1.00 mol = x : 4.00 mol. x = 2.02 g * 4.00 mol : 1.00 mol. x = 8.08 mol. Thus, there are 8.08 g of the sample of 4.00 mol of H2.
Answer:
the size of Ca is the greatest ,then Mg is the greater on size than Be
Explanation:
if you make the electron configuration for each of the elements, what is the main difference u gonna see ?
Be 4 1s2/2s2
Mg 12 1s2 /2s2 2p6/3s2
Ca 20 1s2 /2s2 2p6/3s2 3p6 3d/4s2
see that all the elements are in the same group but are in different period
u gonna see the last electron valance shell in Ca are too far from its nucleus but in Be the last electrons are too close and more attracted to the atom's nucleus , so the size of Ca is the biggest then Mg then Be
Answer:
15.89%
Explanation:
To calculate the percentage of carbon in BeC2O4•3H2O, first we calculate the molar mass of BeC2O4•3H2O
MM of BeC2O4•3H2O = 9+(12x2)+(4x16)+3(2+16) = 9+24+64+54 =151g/mol
Mass of C in BeC2O4•3H2O = 2x12 = 24g
%Mass of carbon in BeC2O4•3H2O = (24/151) x 100
= 15.89%
First, convert grams of the elements to moles. Then you divide by the smallest number of moles to get the lowest whole number ratio.
86g C×1 mol C/12g C = 7.2 mol C/7.2= 1
14 g H×1 mol H/1g H = 14 mol H/7.2= 2
So the empirical formula is C1H2