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dezoksy [38]
3 years ago
6

Five gases combined in a gas cylinder have the following partial pressures: 3.00 atm (N2), 1.80 atm (O2), 0.29 atm (Ar), 0.18 at

m (He), and 0.10 atm (H). What is the total pressure that is exerted by the gases?
Chemistry
2 answers:
lisov135 [29]3 years ago
5 0

This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:<span>


<span>P = 3.00 atm + 1.80 atm + 0.29 atm + 0.18 atm + 0.10 atm</span></span>

<span><span>P = 5.37 atm</span></span>

Law Incorporation [45]3 years ago
5 0

the answer is 5.37 atm

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Throughout the explanation section, the reason behind the given statement is described.

Explanation:

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Which half-reaction correctly represents reduction? *
nasty-shy [4]

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3 0
3 years ago
I need answers to question 1,2,3
sashaice [31]

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

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Mole of Ca(NO₃)₂ =?

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Mole of Ca(NO₃)₂ = 0.61 mole

6 0
2 years ago
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