Harmonics, Loop and Harmonic number
Hope this helps :)
Answer:
75ohms
Explanation:
V= IR
V = 1.5volts
I = 0.02A
1.5 = 0.02×R
Making R the subject
R = 1.5/0.02
R = 75ohms
The resistance in the circuit will be 75ohms
When capacitors are in PARALLEL, they add up. (like resistors in series)
If you connect these four capacitors in parallel, the combination behaves like a single capacitor of (4 x 2.5) = 10 mF.
That's the greatest capacitance you can make with these four pieces.
Answer:
The steam will start to condense at 6.6 mm into the pipe
Explanation:
The volume flow rate =π×(50/1000)²/4×10 = 0.0196 m³/s
The specific volume of the steam = 1.769 m³/kg
Therefore;
The mass flow rate = 0.0196/1.769 = 0.011099 kg/s
The resistance of the insulation material = ln(0.075/0.05)/(2×π×0.075) = 0.860 K/W
The resistance of the outside film of the insulator = 1/(15×2×π×0.075×1) = 0.14147 K/W
The total resistance = 0.14147 + 0.860 = 1.00147 K/W
1/(UA) = 1.00147 K/W
A = 2×π×0.05×1
1/U = 0.3146
U = 3.178 W/m² K
We have;
T(x) = T₀ + (Tin - T₀) exp(-UπDx/mcp)
Therefore, when T(x) = 100°C, we have;
100 = 20 + (120 - 20)exp(-3.178×π×0.05x/(0.011099 × 1.33))
Solving, we get
x = 6.597× 10⁻³ m ≈ 6.6 mm
Therefore, the steam will start to condense at 10 mm into the pipe.
