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torisob [31]
3 years ago
14

How much work must be done to bring three electrons from a great distance apart to within 9.0 × 10-10 m from one another (at the

corners of an equilateral triangle)?
Physics
1 answer:
ludmilkaskok [199]3 years ago
5 0

As we know that change in the potential energy of the system must be equal to the work done to bring the system of charges

here we know that

U = 3\frac{kq_1q_2}{r^2}

also here we have

q_1 = q_2 = 1.6 \times 10^{-19} C

r = 9 \times 10^{-10} C

now we will have

U = \frac{9 \times 10^9 (1.6 \times 10^{-19})^2}{(9\times 10^{-10})^2}

U = 2.84 \times 10^{-10} J

So here work done to bring three charges at the vertices of a triangle is given as

W = 2.84 \times 10^{-10} J

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(a) What is the fluid speed in a fire hose with a 9.00-cm diameter carrying 80.0 L of water per second? (b) What is the flow rat
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Answer:

12.5752053801 m/s

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No.

Explanation:

Q = Volume flow rate = 80\ L/s=80\times 10^{-3}\ m^3/s

d = Diameter of pipe = 9 cm

A = Area = \dfrac{\pi}{4}d^2

Volume flow rate is given by

Q=Av\\\Rightarrow v=\dfrac{Q}{A}\\\Rightarrow v=\dfrac{80\times 10^{-3}}{\dfrac{\pi}{4} (9\times 10^{-2})^2}\\\Rightarrow v=12.5752053801\ m/s

Velocity of fluid is 12.5752053801 m/s

The volume flow rate in m³/s is 80\times 10^{-3}\ m^3/s

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Question 7 of 25
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Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

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Explanation:

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In the above reaction;

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The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na,  one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

6 0
2 years ago
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