Answer:
The answer is below
Explanation:
The resistance of a conductor (R) is given by:
and ρ is resistivity
The length = 20cm = 0.2 m
The tube has an outer diameter of 1.1 cm (0.011 m), hence the outer area is:
A₁ = π * diameter²/4 = π * 1.1²/4 = 0.000095 m²
The tube has an inner diameter of 0.85 cm (0.0085 m), hence the inner area is:
A₂ = π * diameter²/4 = π * 0.0085²/4 = 0.0000567 m²
The conductor area = outer area - inner area = 0.000095 m² - 0.0000567 m² = 0.0000383 m²
Hence, the resistance is:
The weight of the ant is the force that acts on the anthill in the <u>downward direction</u> and at angle of 30° rom the vertical.
<u>Given the following data:</u>
- Angle of inclination = 30.0°.
<h3>What is a
free-body diagram?</h3>
In Science, a free-body diagram can be defined as a graphical illustration which is typically used to visualize moments, tension, and applied forces that are acting on an isolated or rigid body (object) while using arrows pointing in the direction of these forces.
In this scenario, the weight of the ant is the force that acts on the anthill in the <u>downward direction</u> and at angle of 30° rom the vertical.
Read more on free-body diagram here: brainly.com/question/18770265
The distance covered by the object between t =4 s and t = 6 s is 4 m
Explanation:
In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.
Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.
We see that we have to calculate the area of a triangle, with:
Base:
And height:
Therefore, the area is
So, the distance covered by the object is 4 m.
Learn more about distance:
brainly.com/question/3969582
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Answer:
Explanation:
given,
moles of air compressed, n = 1.70 mol
initial temperature, T₁ = 390 K
Power supply by the compressor, P = 7.5 kW
Heat removed = 1.3 kW
Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.
Time of compression = time of the hay revolution
=
=
=
=0.273 s
Using first law of thermodynamics
U = Q - W
now,
Power supplied 
= 7.5 kW
heat removed 
= 1.3 kW
now,
we know,
C_v for air = 5 cal/° mol
= 5 x 4.186 J/mol°C = 20.93 J/mol°C
now,
the temperature change per compression stroke is equal to 47.57°C.
The amount of solid does not affect how you are describing the solid so a is the answer
