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Karolina [17]
3 years ago
14

WHAT IS THE SPEED OF LIGHT?

Physics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

speed of light: 299,792,458

what does light travel fasted through?: Light will have the fastest velocity when it travels through the air. Light will have the slowest velocity when it travels through gelatin. Why? Light slows down when passing through different transparent materials. The more it slows down, the more it bends when it hits a medium made of that material

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3.) A 20cm long tube has an inner diameter of 0.85cm and an outer
IceJOKER [234]

Answer:

The answer is below

Explanation:

The resistance of a conductor (R) is given by:

R=\frac{\rho L}{A}\\\\where\ L \ is\ the\ conductor\ length\ and \ A\ is\ the\ cross\ sectional\ area and ρ is resistivity

The length = 20cm = 0.2 m

The tube has an outer diameter of 1.1 cm (0.011 m), hence the outer area is:

A₁ = π * diameter²/4 = π * 1.1²/4 = 0.000095 m²

The tube has an inner diameter of 0.85 cm (0.0085 m), hence the inner area is:

A₂ = π * diameter²/4 = π * 0.0085²/4 = 0.0000567 m²

The conductor area = outer area - inner area = 0.000095 m² - 0.0000567 m² = 0.0000383 m²

Hence, the resistance is:

R=\frac{\rho L}{A} =\frac{1.7*10^{-8}*0.2}{0.0000383}=0.00009\ ohm

7 0
3 years ago
An ant climbs at a steady speed up the side of its
lianna [129]

The weight of the ant is the force that acts on the anthill in the <u>downward direction</u> and at angle of 30° rom the vertical.

<u>Given the following data:</u>

  • Angle of inclination = 30.0°.

<h3>What is a free-body diagram?</h3>

In Science, a free-body diagram can be defined as a graphical illustration which is typically used to visualize moments, tension, and applied forces that are acting on an isolated or rigid body (object) while using arrows pointing in the direction of these forces.

In this scenario, the weight of the ant is the force that acts on the anthill in the <u>downward direction</u> and at angle of 30° rom the vertical.

Read more on free-body diagram here: brainly.com/question/18770265

8 0
2 years ago
The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?
Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

b=6-4 = 2

And height:

h=4-0 = 4

Therefore, the area is

A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0
4 years ago
A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
QveST [7]

Answer:

\Delta \theta = 47.57^{\circ} C

Explanation:

given,

moles of air compressed, n = 1.70 mol

initial temperature, T₁ = 390 K

Power supply by the compressor, P = 7.5 kW

Heat removed = 1.3 kW

Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.

Time of compression = time of the hay revolution

             =\dfrac{1}{2}\ T

             =\dfrac{1}{2}\times \dfrac{1}{f}

             =\dfrac{1}{2}\times \dfrac{1}{1.833}

             =0.273 s

Using first law of thermodynamics

U = Q - W

now,

\dfrac{\Delta U}{\Delta t} = \dfrac{\Delta Q}{\Delta t}- \dfrac{\Delta W}{\Delta t}

Power supplied \dfrac{\Delta W}{\Delta t} = 7.5 kW

heat removed \dfrac{\Delta Q}{\Delta t} = 1.3 kW

now,

\dfrac{\Delta U}{\Delta t} = 7.5 -1.3

\dfrac{\Delta U}{\Delta t} = 6.2 kW

we know,

\dfrac{\Delta U}{\Delta t}=\dfrac{nC_v\Delta \theta}{\Delta t}

 C_v for air = 5 cal/° mol

                   = 5 x 4.186 J/mol°C  = 20.93 J/mol°C

now,

\Delta \theta = \dfrac{\Delta U}{\Deta t}\times \dfrac{\Delta t}{n C_v}

\Delta \theta = 6.2\times 10^3 \times \dfrac{0.273}{1.7\times 20.93}

\Delta \theta = 47.57^{\circ} C

the temperature change per compression stroke is equal to 47.57°C.

4 0
3 years ago
ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on
Dafna11 [192]
The amount of solid does not affect how you are describing the solid so a is the answer
5 0
4 years ago
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