15.0 N object is pulled up an inclined plane at constant velocity. If the inclined plane makes an
1 answer:
Answer:
3.69 N
Explanation:
Draw a free body diagram. There are four forces acting on the object:
Weight force W pulling straight down.
Normal force N pushing perpendicular to the inclined plane.
Friction force f pushing down the inclined plane.
Applied force P pushing up the inclined plane.
Sum of forces in the perpendicular direction:
∑F = ma
N − W cos θ = 0
N = W cos θ
Friction force is normal force times the coefficient of friction:
f = Nμ
f = Wμ cos θ
Plug in values:
f = (15.0 N) (0.300) cos 35.0°
f = 3.69 N
You might be interested in
Answer:
Yes, if the system has friction, the final result is affected by the loss of energy.
Explanation:
The result that you are showing is the conservation of mechanical energy between two points in the upper one, the energy is only potential and the lower one is only kinetic.
In the case of some type of friction, the change in energy between the same points is equal to the work of the friction forces
= ΔEm
=
-Em₀
As we can see now there is another quantity and for which the final energy is lower and therefore the final speed would be less than what you found in the case without friction.
=
+ Em₀
Remember that the work of the rubbing force is negative, let's write the work of the rubbing force explicitly, to make it clearer
½ m v² = -fr d + mgh
v = √(-fr d 2/m + 2 gh)
v = √ (2gh - 2fr d/m)
Now it is clear that there is a decrease in the final body speed.
Consequently, if the system has friction, the final result is affected by the loss of energy.