15.0 N object is pulled up an inclined plane at constant velocity. If the inclined plane makes an
1 answer:
Answer:
3.69 N
Explanation:
Draw a free body diagram. There are four forces acting on the object:
Weight force W pulling straight down.
Normal force N pushing perpendicular to the inclined plane.
Friction force f pushing down the inclined plane.
Applied force P pushing up the inclined plane.
Sum of forces in the perpendicular direction:
∑F = ma
N − W cos θ = 0
N = W cos θ
Friction force is normal force times the coefficient of friction:
f = Nμ
f = Wμ cos θ
Plug in values:
f = (15.0 N) (0.300) cos 35.0°
f = 3.69 N
You might be interested in
Answer:
The density of the woman is 950.8 kg/m³
Explanation:
Given;
fraction of the woman's volume above the surface = 4.92%
then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%
the specific gravity of the woman
The density of the woman is calculate as;
Density of fresh water = 1000 kg/m³
Density of the woman = 0.9508 x 1000 kg/m³
Density of the woman = 950.8 kg/m³
Therefore, the density of the woman is 950.8 kg/m³
Answer:
Explanation:
<u>Motion With Constant Acceleration </u>
It's a type of motion in which the velocity of an object changes uniformly over time.
The equation that describes the change of velocities is:
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
Solving the equation for a:
The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.
The acceleration is:
Answer:
The voltage across the capacitor is 1.57 V.
Explanation:
Given that,
Number of turns = 10
Diameter = 1.0 cm
Resistance = 0.50 Ω
Capacitor = 1.0μ F
Magnetic field = 1.0 mT
We need to calculate the flux
Using formula of flux
Put the value into the formula
We need to calculate the induced emf
Using formula of induced emf
Put the value into the formula
Put the value of emf from ohm's law
We know that,
We need to calculate the voltage across the capacitor
Using formula of charge
Put the value into the formula
Hence, The voltage across the capacitor is 1.57 V.