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3 years ago

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Mary is at the top of a 25 m steep slide. She is then pushed and starts accelerating at a rate of 4.3 m/s"2. How long will it ta

ke her to get to the bottom of the slide?

1 answer:

Gemiola [76]3 years ago

8 0

<u>Answer</u>

3.4 s

<u>Explanation</u>

The question can be solve by using the 2nd Newton's law of motion.

s = ut + 1/2at²

Before she is pushed, the initial velocity is zero.

u = 0

Now the equation becomes

s = 0 + 1/2at²

s = 1/2at²

25 = 1/2 × 4.3 × t²

50 = 4.3t²

t² = 50/4.3

= 11.628

t = √11.628

= 3.4 s

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Answer:

1.195 m

2.8375 s

2.21433 rad/s

Explanation:

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N = Number of cycles = 8

t = Time to complete 8 cycles = 22.7 s

Radius would be equal to the distance divided by 2

$r=\frac{d}{2}\\\Rightarrow r=\frac{2.39}{2}\\\Rightarrow r=1.195\ m$

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Time period would be given by

$T=\frac{t}{N}\\\Rightarrow T=\frac{22.7}{8}\\\Rightarrow T=2.8375\ s$

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notka56 [123]

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2 years ago

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Nimfa-mama [501]

Answer:

Power your home with renewable energy.

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Explanation:

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3 years ago

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Answer:

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Given:

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mass of filled can, $m_f=0.369\ kg$

weight of empty can, $w_c=0.153\ N$

<u>So, mass of the empty can:</u>

$m_c=\frac{w_c}{g}$

$m_c=\frac{0.153}{9.81}$

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bonufazy [111]

Answer:

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